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3 years ago

How do you expand brackets

Mathematics

1 answer:

Olenka [21]3 years ago

7 0

Answer:

multiply each term in the bracket by the expression outside the bracket

Step-by-step explanation:

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G(x)= x^2+1 and g(2k)=101, then k= ?

vlabodo [156]

I hope this helps you

4 0

4 years ago

Evaluate \dfrac{e}{4}+2f-3

Igoryamba

Answer:

The value of given expression is 1.

Step-by-step explanation:

Consider the given expression is

$\dfrac{e}{4}+2f-3$

When e=12 and $f=\dfrac{1}{2}$ .

Substitute e=12 and $f=\dfrac{1}{2}$ in the given expression.

$\dfrac{12}{4}+2(\dfrac{1}{2})-3$

On simplification we get

$3+1-3$

$1$

Therefore, the value of given expression is 1.

8 0

3 years ago

15/3 = ?/1. what's the missing unit rate

tamaranim1 [39]

The unit rate is 5/1

15/3=5
3/3=1

7 0

3 years ago

Read 2 more answers

To estimate the mean score μ μ of those who took the Medical College Admission Test on your campus, you will obtain the scores o

Juliette [100K]

Answer: 0.4667

Step-by-step explanation:

According to 68–95–99.7 rule , About 99.7% of all data values lies with in 3 standard deviations from population mean ( $\mu$ ).

Here , margin of error = 3s , where s is standard deviation.

As per given , we have want our sample mean $\overline{x}$ to estimate μ μ with an error of no more than 1.4 point in either direction.

If 99.7% of all samples give an $\overline{x}$ within 1.4 , it means that

$3s=1.4$

Divide boths ides by 3 , we get

$s=0.466666666667\approx0.4667$

Hence, So $\overline{x}$ must have 0.4667 as standard deviation so that 99.7 % 99.7% of all samples give an $\overline{x}$ within 1.4 point of μ .

6 0

4 years ago

Which expression would be equivalent to: Which expression would be equivalent to: \frac{1+b}{2} - 3(a-1)

IrinaVladis [17]

Answer:

$\frac{1+b}{2} - 3(a-1) = \frac{b- 6a+7}{2}$

Step-by-step explanation:

Given

$\frac{1+b}{2} - 3(a-1)$

Required

An equivalent expression

$\frac{1+b}{2} - 3(a-1)$

Take LCM

$\frac{1+b}{2} - 3(a-1) = \frac{1+b- 2*3(a-1)}{2}$

$\frac{1+b}{2} - 3(a-1) = \frac{1+b- 6(a-1)}{2}$

Open bracket

$\frac{1+b}{2} - 3(a-1) = \frac{1+b- 6a+6}{2}$

Collect like terms

$\frac{1+b}{2} - 3(a-1) = \frac{b- 6a+6+1}{2}$

$\frac{1+b}{2} - 3(a-1) = \frac{b- 6a+7}{2}$

Hence, an equivalent expression is:

$\frac{b- 6a+7}{2}$

8 0

3 years ago