3 years ago

I need help as soon as possible

Mathematics

1 answer:

ElenaW [278]3 years ago

7 0

I think the equation might be -5+8 ????

idrk

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Well I'm having troubles with something I have no idea what it is or how to do it. The problem is x^2 -18x+8=0. I only know how

Lubov Fominskaja [6]

Answer:

$x = \frac{-(-18) -\sqrt{(-18)^2 -4*1*8}}{2} = \frac{18 -2 \sqrt{73}}{2}= 9 -\sqrt{73}$

$x = \frac{-(-18) +\sqrt{(-18)^2 -4*1*8}}{2} = \frac{18 +2 \sqrt{73}}{2}= 9 +\sqrt{73}$

Step-by-step explanation:

We have the following equation:

$x^2 -18 x +8 =0$

We can use the quadratic formula given by:

$x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}$

Where:

$a = 1 , b=-18, c =8$

And replacing we got:

$x = \frac{-(-18) -\sqrt{(-18)^2 -4*1*8}}{2} = \frac{18 -2 \sqrt{73}}{2}= 9 -\sqrt{73}$

$x = \frac{-(-18) +\sqrt{(-18)^2 -4*1*8}}{2} = \frac{18 +2 \sqrt{73}}{2}= 9 +\sqrt{73}$

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