AthXL for School

The color distribution of Skittles is the following: 10% blue, orange, and green each, 23.3333% yellow, red, and purple each. In

irina1246 [14]

Answer:

No

Step-by-step explanation:

Given that:

Percentage of blue, orange and green = 10%

Percentage of yellow, red and purple = 23.3333%

Number of skittles in bag by color :

Red = 137

Orange = 39

Yellow = 130

Green = 39

Blue = 43

Purple = 112

According to the color distribution :

Number of blue, orange and green should be the same and also number of yellow, red and purple skittles must be the same.

Total number of skittles :

(137 + 39 + 130 + 39 + 43 + 112) = 500

10% of the total = 0.1 * 500 = 50

Hence,

We should have 50 blue, orange and green skittles

23.33333% of total = 116.666 (about 117 skittles of yellow, red and purple color)

3 0

2 years ago

Given that the expression 2x² -2.9x-3.6 can be factorized into the form 0.1(px+q)(rx+s), where p, q, r and s are integers, find

Nonamiya [84]

$~~2x^2-2.9x-3.6\\\\=\dfrac{20}{10}x^2 - \dfrac{29}{10} x-\dfrac{36}{10} \\\\=\dfrac 1{10} (20x^2 -29x -361)\\\\=0.1(20x^2-29x-36)\\\\=0.1(20x^2-45x+16x-36)\\\\=0.1[5x(4x-9)+4(4x-9)]\\\\=0.1(5x+4)(4x-9)\\\\\text{Where,}~ p=5, ~ q=4,~ r=4~,s=-9\\\\\text{Hence,}~ \\\\p+q+r+s \\\\ = 5+4+4 -9 \\\\=13-9 \\\\ =4$

3 0

2 years ago

Factorise: 4x squared - 9y squared

kicyunya [14]

Here is your great answer Simplifying
4x2y + 12xy2 + 9y3

Reorder the terms:
12xy2 + 4x2y + 9y3

Factor out the Greatest Common Factor (GCF), 'y'.
y(12xy + 4x2 + 9y2)

Factor a trinomial.
y((2x + 3y)(2x + 3y))

Final result:
y(2x + 3y)(2x + 3y)

4 0

3 years ago

Simplify the xepression 10(x + 2)

lions [1.4K]

Answer: 10x + 20

Step-by-step explanation:

10 (x + 2)

Distribute

10x + 20

3 0

3 years ago

Read 2 more answers

Are the events "selecting a female" and "selecting a students who has brown eyes" independent?

Deffense [45]

Answer:

No, the events are not independent.

Step-by-step explanation:

Suppose that there are two events, A and B.

Such that first happens the event A and then the event B.

If the outcome of event A affects the probabilities for the different outcomes of event B, then the events are dependent.

In this case, if we have only the event "selecting a student who has brown eyes" (at random)

The probability is equal to the quotient between the total number of students with brown eyes, and the total number of students, then this probability is:

P = 91/200 = 0.455...

Now, if we first impose the "selecting a female", now when we want to select a student with brown eyes we will look only at the female students.

In this case, there are 32 with brown eyes and a total of 90 female students, then the probability of selecting a female with brown eyes at random is:

P = 32/90 = 0.355...

So the probability is different, which means that the events "selecting a female" and "selecting a student who has brown eyes" are not independent.

4 0

3 years ago