Question

F (x) = x2 + 4 What is the value of x when f (x) = 42 A. -2 В. 0 C 12 D. 20

Answer 1

Answer:

f(x)=X^2+4

f(x)=42

42=X^2+4

X^2+4=42

X^2=42-4

X^2=38

X=sqrt(38)=6.16

$\sqrt{?}$