To find the area of the arena, you will need to find the areas of the rectangular spaces and the 2 semicircles. Because the formulas are given, I will just substitute in the values and show the work for finding the areas.
To find the perimeter, you will look at the distances of lines that take you around the space. Because two of these spaces are half circles, you will need to find the circumference of the full circle.
Also, the answers need to be given in meters, so all units given in centimeters will be divided by 100 to convert them to meters.
Perimeter:
C= 3.14 x 20 m
C = 62.8 meters
62.8 + 8 + 25 + 8 + 5 + 8 + 10 + 8 + 40= 174.8 meters for the Perimeter
Area:
A = 25 x 8
A = 200 square meters
A = 10 x 8
A = 80 square meters
A = 20 x 40
A = 800 square meters
A = 3.14 x 10^2
A = 314 square meters
Total Area: 314 + 800 + 80 + 200= 1394 square meters
Answer:
b=i*
or -i*
Step-by-step explanation:
11b^2-9=-68
11b^2=-59
b^2=-59/11
b=i* or -i*
"i" in this case is an imaginary number, equal to 
if you haven't learned about these yet, something is wrong with the question
Try to divide by each prime number starting with 2. If it is divisible, keep trying the same prime number until it is not divisible. Then move on to the next prime number, 3. Keep dividing until you get 1. All the prime numbers you divided by are the prime factorization.
List of the first several prime numbers: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29
Start with 85.
85 is not divisible by 2.
Move on to 3.
85 is not divisible by 3.
Move on to 5.
85/5 = 17
17 is a prime number, so now divide 17 by 17.
17/17 = 1
We divided just by 5 and 17.
Answer: The prime factors of 85 are 5 and 17.
Procedure:
1) calculate the number of diferent teams of four members that can be formed (with the ten persons)
2) calculate the number of teams tha meet the specification (two girls and two boys)
3) Divide the positive events by the total number of events: this is the result of 2) by the result in 1)
Solution
1) the number of teams of four members that can be formed are:
10*9*8*7 / (4*3*2*1) = 210
2) Number of different teams with 2 boys and 2 girls = ways of chosing 2 boys * ways of chosing 2 girls
Ways of chosing 2 boys = 6*5/2 = 15
Ways of chosing 2 girls = 4*3/2 = 6
Number of different teams with 2 boys and 2 girls = 15 * 6 = 90
3) probability of choosing one of the 90 teams formed by 2 boys and 2 girls:
90/210 = 3/7
