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den301095 [7]
3 years ago
5

If x2 - 6x - 16, what are the x-intercepts?​

Mathematics
2 answers:
romanna [79]3 years ago
8 0
If that’s meant to be x^2 - 6x - 16
Then factorise to (x+2)(x-8)
So x intercepts are -2 and 8
Nana76 [90]3 years ago
6 0

Answer:

(-2, 0) and (8, 0)

Step-by-step explanation:

x2 - 6x - 16 = 0

(x - 8)(x + 2) = 0

x = -2, 8.

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