12x²-9x = 0
3x(4x-3)=0
4x-3=0
4x=3
x=3/4
so either x = 0 or x = 3/4
Answer:
Step-by-step explanation:
There is no pair of real numbers that have a total of -4 and a product of 5. The complex numbers (-2+i) and (-2-i) will meet your requirements.
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If the numbers of interest are 'a' and 'b', they will be zeros of the quadratic whose factored form is ...
(x -a)(x -b) = 0
Expanding that, we find an opportunity to use the given sum and product numbers:
x² -(a+b)x +ab = 0
x² -(-4)x +5 = 0
Rewriting this in vertex form gives ...
(x² +4x +4) +1 = 0
(x +2)² +1 = 0
We can find the values of x by subtracting 1 and taking the square root.
(x +2)² = -1
x +2 = ±√(-1) = ±i
x = -2±i
The two numbers of interest are -2+i and -2-i.
To find the terms, multiply by .5
5, .5 times 5 = 2.5, .5 times 2.5 = 1.25, .5 times 1.25 = .625, .5 times .625 = .3125
Step-by-step explanation:
x²+2x+1
x²+x+x+1
x(x+1)1(x+1).
(x+1)(x+1)
x=-1. , x=-1
Answer:
o(-2,-1)
Step-by-step explanation:
Let point A be initial point and A' be terminal point.
A(-7,3), A'(x,y) and V=(5,-4)
V=(Xf-Xi,Yf-Yi)
(5,-4)=(x-(-7),y-3)
(5,-4)=(x+7,y-3)
5=x+7. -4=y-3
5-7=x. -4+3=y
x=-2. y=-1
A'=(-2,-1)
