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damaskus [11]
2 years ago
11

Find the inverse function

Mathematics
2 answers:
drek231 [11]2 years ago
8 0

Answer:

f^-1(x) = ( x + -1 )³

Step-by-step explanation:

f(x) = ∛x + 1

y  = ∛x + 1

we have to make x the subject to find the inverse

y  = ∛x + 1

y - 1 = ∛x

( y - 1 )³ = x

so Inverse: f^-1(x) = ( x + -1 )³

Hoochie [10]2 years ago
4 0
(?) is (-1) and that gray blank thing is 3.
Give a brainliest please:-)

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Why are the triangles congruent?
MariettaO [177]

Answer:

SAS (side angle side)

Step-by-step explanation:

the third one

4 0
2 years ago
Read 2 more answers
Find the missing term of the arithmetic sequence<br> 17,____,23
Kruka [31]

Answer:20

Step-by-step explanation:

17 + 3 = 20

20 + 3 = 23

8 0
3 years ago
What does the quadratic function f(x)=x^2-10x+9 look like when it is rewritten in the form f(x) = a (x-h) + k
Tatiana [17]

ANSWER

When f(x)=x^2-10x+9 is written in the form f(x)=a(x-h)^2+k, it looks like f(x)=(x-5)^2-16


EXPLANATION

To write  f(x)=x^2-10x+9 in the form f(x)=a(x-h)^2+k, we have to complete the squares.


We add and subtract half the coefficient of x square.


f(x)=x^2-10x+(-5)^2-(-5)^2+9


The first three terms of the function is now a perfect square.

f(x)=(x-5)^2-25+9

We now simplify rto obtain,

\Rightarrow f(x)=(x-5)^2-16





6 0
3 years ago
It would mean a lot.
LUCKY_DIMON [66]
First, subtract y2 - y1 to find the vertical distance. Then, subtract x2 - x1 to find the horizontal distance.

Formula to find distance given two points.

Square root (X2 - X1)^2 + (Y2 - Y1)^2

Xa Ya Xb Yb
A = (3, -4) B = (-1, 3)

Xa goes into X2 and Xb goes into X1

(3 - (-1))^2

Ya goes into Y2 and Yb goes into Y1

(-4 - 3)^2

Square root (3 - (-1))^2 + (-4 - 3)^2

Square root (4)^2 + (-7)^2

Square root 16 + 49

Square root 65

= 8.06

The error was Drako had (3 - 4)^2 when it should have been (3 - (-4))^2 because a positive is subtracting a negative.
6 0
2 years ago
The limit as h approaches 0 of (e^(2+h)-e^2)/h is ?
Whitepunk [10]
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h

</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
3 0
3 years ago
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