Answer:
The correct answer is C. A stationary front that will cause an extended period of clouds or precipitation means packing rain gear and planning for precipitation during your trip.
Explanation:
The stationary front is a meteorological front on the border of cold and warm air, more common in summer. It is most often the limit of polar and mid-latitude air masses. It usually lasts in place for a maximum of a few days. The stationary front resembles a warm front or a slow cold front. The weather in the stationary front area is variable, often cloudy and often still rainy. In a few days, the stationary front will turn into either a cold or warm front, or its clouds will disintegrate.
The cooling rate of the substance is approximately 0.0732.
According to the statement, the Newton's law of cooling is defined by the following formula:
(1)
Where:
- Final temperature, in degrees Celsius.
- Initial temperature, in degrees Celsius.
- Time, in minutes.
- Cooling rate, in
.
- Current temperature, in degrees Celsius.
Please notice that substance reaches thermal equilibrium when
, that is when temperature of the substance is equal to the temperature of surrounding air.
If we know that
,
,
and
, then the cooling rate of the substance is:





The cooling rate of the substance is approximately 0.0732.
To learn more on Newton's law of cooling, we kindly invite to check this verified question: brainly.com/question/13748261
Answer:
6m ramp
Explanation:
I'm assuming you need the ramp which will make it the easiest which would be the 6m ramp because since it is longer it will be a more gradual incline making it easier to move the boxes.
Answer:
I used the function 1-proportion z-interval on the calculator, where I inputted
- Successes(x) = 64
- Sample size(n) = 593
- Confidence Level(C level) = 0.99
It would result in zInterval_1Prop 64,593,0.99: stat.results, where the values are shown below as:
- Lower bound (CLower) = 0.075105
- Upper bound (CUpper) = 0.140747
- test statistic (p^) = 0.107926
- Margin of error (ME) = 0.032821
Therefore, the 99% confidence interval would be around 0.11 ± 0.03 or range from 0.08 to 0.14.
<em><u>Note: not sure if this is correct</u></em><em> O_o</em>