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nevsk [136]
2 years ago
15

Write and equation of the line in slope intercept form that passes through the points. (0,1) (2,4)

Mathematics
1 answer:
Helen [10]2 years ago
8 0
Y = 3x + 1

slope: (y2-y1)/(x2-x1) = (4-1)/(2-1) = 3/1 = 3

point slope form:
y-y1 = m (x-x1)
y-1 = 3 (x-0)
y-1 = 3x
y = 3x + 1
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A magazine can layout 1/16 of an issue in 3 days. How many days does it take to layout one issue?
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please help!!! the study conducted was 6 days long: there was 72mm of plant food and it decreased an equal amount each day.
Anuta_ua [19.1K]

Answer:

f(x) = 72 - 12x

Step-by-step explanation:

No. of days of study = 6

Amount of food to use for the 6 days = 72 mm

Given that equal amount of food was used each day, amount used per day = \frac{72}{6} = 12 mm

This would enable us derive a function for the amount of food remaining f(x), which can be expressed as a function of the number of days that have passed, (x).

Thus, we would have:

f(x) = 72 - 12x

Let's check if this equation expresses the relation of the function well.

At the end of day 1, if we used, 12mm, we would have 72 - 12 = 60mm of food remaining.

If we replace x in the equation we derived, we would get the same 60mm as the amount of food remaining.

If you try 2, 3, 4, 5 days, you'd get same thing.

At the end of the study, after the 6th day, the food would remain nothing.

Replace 6 for x in the relation function derived, you'd get a value of 0.

6 0
3 years ago
Although companies would like consumers to believe that Identity theft protection is an
stiks02 [169]

The obtained answers for the given frequency distribution are:

(a) The formula for the mean in sigma notation is \bar x =\frac{1}{n}  \sum X_i where n is the number of observations; X_i are the n observations.

The mean for the given monthly plan price is $16.1.

(b) The frequency distribution for given data is {$9.99 - 2; $10 - 5; $12 - 1; $12.75 - 2; $14.99 - 6; $20 - 4; $25 - 5}

(c) The formula for the mean using the frequency distribution table is \bar x = \frac{1}{N}\sum f_ix_i where N =\sum f_i and on applying this formula for the given data, the mean is $16.1.

(d) The median for the given data is m_e = 14.99, and the mode for the given data is $14.99

<h3>What are the mean, median, and mode for a frequency distribution?</h3>

The frequency distribution has sample observations x_i and frequencies f_i.

Then, the mean is calculated by

\bar x = \frac{1}{N}\sum f_ix_i

Where N =\sum f_i (Sum of frequencies)

The median is calculated by

m_e=\left \{ {{x_{k}} \ if \ n = 2k+1 \atop {\frac{x_{k}+x_{k+1}}{2}} \ if \ n =2k} \right.

The mode is calculated by

Mode = highest frequency value

<h3>Calculation:</h3>

The given list of data is

{$14.99, $12.75, $14.99, $14.99, $9.99, $25, $25, $10, $14.99, $10, $20, $10, $20, $14.99, $10, $25, $20, $12, $14.99, $25, $25, $20, $12.75, $10, $9.99}

(a) Formula for the mean using sigma notation and use it to calculate the mean:

The formula for the mean is

\bar x =\frac{1}{n}  \sum X_i

Where n = 25; X_i - n observations

On substituting,

Mean \bar x

=1/25(14.99+12.75+14.99+14.99+9.99+25+25+10+14.99+10+20+10+20+14.99+10+25+20+12+14.99+25+25+20+12.75+10+9.99)

= 1/25(402.42)

= 16.09 ≅ 16.1

(b) Constructing a frequency distribution for the data:

Cost - frequency - cumulative frequency

$9.99 - 2 - 2

$10 - 5 - 7

$12 - 1 - 8

$12.75 - 2 - 10

$14.99 - 6 - 16

$20 - 4 - 20

$25 - 5 - 25

Sum of frequencies N = 25;

(c) Using frequency distribution, calculating the mean:

The formula for finding the mean using frequency distribution is

\bar x = \frac{1}{N}\sum f_ix_i

Where N = 25;

On substituting,

\bar x<em> </em>= 1/25 (2 × 9.99 + 5 × 10 + 1 × 12 + 2 × 12.75 + 6 × 14.99 + 4 × 20 + 5 × 25)

  = 1/25 (402.42)

  = 16.09 ≅ 16.1

Therefore, the mean is the same as the mean obtained in option (a).

(d) Calculating the median and the mode:

Since N = 25(odd) i.e., 2· 12 + 1; k = (12 + 1)th term = 13th term

So,  the median m_e = 14.99. (frequency at 13th term)

Since the highest frequency is 6 occurred by the cost is $14.99,

Mode = 14.99

Learn more about frequency distribution here:

brainly.com/question/27820465

#SPJ9

7 0
2 years ago
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