Answer:
25 times 20 = 500 and then 25 times 10 = 250
30 = 750
Step-by-step explanation:
<em>25*20=500 </em>
<em>25*10=250</em>
<em>500+250</em>
<em>= 750</em>
Sorry if late!
Hope this helps.
Have a great day and good luck!
Brainliest is appreciated!
-Lea
Answer:
He would need to walk the dog 6 more times because 8 times 11 is 88 and if he has already walked the dog 5 times you would subtract that from 11 to get 6. So the answer would be 6
Step-by-step explanation:
8·11= 88
11-5= 6
The value of the side c will be 5.56 cm and angle C is 32.49° and angle B is 42.51°.
<h3>What is law of cosine?</h3>
Let there is a triangle ABC such that |AB| = a units, |AC| = b units, and |BC| = c units and the internal angle A is of θ degrees, then we have:
a² + b² – 2ab cos C = c²
Given triangle ABC, A = 105°, a = 10 cm, b = 7 cm.
Then we have
7² + c² – (2 · 7 · c) cos 105° = 10²
c² + 3.62c – 51 = 0
On solving, we have
c = 5.56
Then the angle C will be
10² + 7² – 2 · 7 · 10 · cos C = 5.56²
149 – 140 cos C = 30.91
cos C = 0.8435
C = 32.49°
We know that
∠A + ∠B + ∠C = 180°
105° + ∠B + 32.49° = 180°
∠B = 42.51°
Learn more about law of cosines here:
brainly.com/question/17289163
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72, 96, 84, 12
72 + (7x+24) = 180
7x + 96 = 180
7x = 84
x = 12
Answer: The length of approximately 68% of all pig pregnancies will fall between <u>109 days</u> and <u>119 days</u>.
Step-by-step explanation:
According to the empirical rule , 68% of the population falls within one standard deviations from the mean.
Given : For pigs, the length of pregnancies varies according to a normal distribution with a mean of 114 days and a standard deviation of 5 days.
According to the Empirical Rule, the length of approximately 68% of all pig pregnancies will fall between 
days and 
days .
i.e. the length of approximately 68% of all pig pregnancies will fall between <u>109 days</u> and <u>119 days</u>.
