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lesya [120]
3 years ago
12

The Science Club went on a two-day field trip. The first day the members paid $40 for transportation plus

Mathematics
1 answer:
grin007 [14]3 years ago
3 0

Answer:

day 1 total $60+$15=$75

day 2 total $95+$12=$107

total 2 days = $181

Step-by-step explanation:

i hope this is correct :)

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Write the monomial in standard form. name it's coefficient and identify its degree.
Hunter-Best [27]

Answer:

Standard\ Form = {3n^2} m^{-2}

Step-by-step explanation:

Given

\frac{2}{3m^2n} * 4.5n^3

Required

Write in Standard Form

To start with; the two monomials have to be multiplied together;

\frac{2}{3m^2n} * 4.5n^3

Standard\ Form = \frac{2 * 4.5n^3}{3m^2n}

Split the numerator and the denominator

Standard\ Form = \frac{2 * 4.5 * n^3}{3 * m^2 * n}

Multiply Like terms

Standard\ Form = \frac{9 * n^3}{3 * m^2 * n}

Divide 9 by 3 to give 3

Standard\ Form = \frac{3 * n^3}{m^2 * n}

Divide n³ by n to n²

Standard\ Form = \frac{3 * n^2}{m^2 }

Split fraction

Standard\ Form = {3 * n^2} * \frac{1}{m^2 }

From laws of indices;

\frac{1}{a^n} = a^{-n}

Standard\ Form = {3 * n^2} * \frac{1}{m^2 } becomes

Standard\ Form = {3 * n^2} * m^{-2}

Multiply all together

Standard\ Form = {3n^2} m^{-2}

5 0
3 years ago
The cost of printing a catalog of the products that your company distributes is a flat rate of $52 plus $0.20 per copy. Let C re
marusya05 [52]
The answer is d, just find the equation and then plug in the first few numbers of copies and you’ll find the correct answer

mark me brainliest if the answer is correct, thank you in advance :)
7 0
3 years ago
El diámetro de la ranura de la parte superior de un recipiente metálico es de 1.94 in ¿Cuál
zzz [600]
49.276 mm, (25.4 mm•x in) es la ecuación para convertir las pulgadas a milímetros
5 0
3 years ago
Given:• PQRS is a rectangle.• mZ1 = 50°Р21SRWhat is mZ2?130°85°70°65°
Over [174]

To answer this question, we need to recall that: "the diagonals of a rectangle bisect each other"

Thus, if we assign the point of intersection of the two diagonals in the rectangle as point O, we can say that the triangle OQR is an "isosceles triangle". Note that this is because the lengths OR and OQ are equal since we know that: "the diagonals of a rectangle bisect each other". See the below diagram for clarity.

Now, we have to recall that:

- the base angles of any isosceles triangle are equal. This is a fact, and this means that the angles

- also the sum of all the angles in any triangle is 180 degrees

Now, considering the isosceles triangle OQR, we have that:

\angle OQR+\angle ORQ+\angle ROQ=180^o

Now, since the figure already shows that angle m\angle2+\angle ORQ+50^o=180^oNow, since we have established that the base angles m\angle2+m\angle2+50^o=180^owe can now solve the above equation for m<2 as follows:

\begin{gathered} m\angle2+m\angle2+50^o=180^o \\ \Rightarrow2m\angle2+50^o=180^o \\ \Rightarrow2m\angle2=180^o-50^o \\ \Rightarrow2m\angle2=130^o \\ \Rightarrow m\angle2=\frac{130^o}{2}=65^o \end{gathered}

Therefore, the correct answer is: option D

7 0
1 year ago
Need answer asap, will give brainliest.
Nesterboy [21]

The solution is the point where the lines cross. So (-1, -2)

6 0
3 years ago
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