I am pretty sure it’s c because you go up 4 and over 3 to the right so that would be plus 3
Find the distance between the points t(13, 1.6)t(13, 1.6) and v(5.4, 3.7)v(5.4, 3.7).
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The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:
Thus the distance between points t(13, 1.6) and v(5.4, 3.7) is found using the formula as:
-38 due to the fact the lower the number, the colder it is.
The slope-intercept form of a line is y = mx + b, where m is the slope and b is the y-intercept. Since you are given the slope (0.5) and the y-intercept (3), all you have to do is substitute these given values into the equation. Substituting them in you get: y = 0.5x + 3, which is your answer.
Answer:
x = -8 and x = 4
Step-by-step explanation:
given
f(x) = (x+8) (x - 4)
recall that at any point on the x-axis, y = 0 [i.e f(x) = 0]
hence to find where the graph crosses the x-axis, we simply substitue f(x) = 0 into the equation and solve for x
f(x) = (x+8) (x - 4)
0 = (x+8) (x - 4)
Hence
either,
(x+8) = 0 ----> x = -8 (first crossing point)
or
(x-4) = 0 ------> x = 4 (second crossing point)
Hence the graph crosses the x-axis at x = -8 and x = 4
