Find the volume of the figure of each figure

In △MNP , m∠M=41∘ , m∠P=62∘ , and NP=108 centimeters . What is MP ?

yarga [219]

Um 12 i think dat really look hard

8 0

3 years ago

Read 2 more answers

There are 418 students at a school. Han estimates that they each drink about 5 glasses of water each day.

Sauron [17]

Answer:

Step-by-step explanation:

a) together, they all drink about 2,090 glasses of water in one day. (418 * 5 = 2,090).

b) 2,090 * 7 (7 days in 1 week) = They drink about 14,630 glasses of water in one week.

c) 14,630 * 4 (4 weeks in 1 month) = About 58,520 glasses of water in one month.

d) 1,000,000/58,520 ≈ 17. It would take all of the students about 17 months to drink 1,000,000 glasses of water.

Hope that helps!

6 0

2 years ago

Refer to your math writing journal file named "Lines and Angles." What real-world examples did you describe for the three ways i

Sav [38]

Answer:

Railway lines are example of parallel lines
The floor and the walls of a room are example of perpendicular lines
Two roads crossing at a signal can be termed as example of intersecting lines

Step-by-step explanation:

The lines can be related in following three ways

Lines can be parallel
Lines can be perpendicular
Lines can be intersecting at an angle other than 90.

Now three real life examples of above three scenarios are described below:

Railway lines are example of parallel lines
The floor and the walls of a room are example of perpendicular lines
Two roads crossing at a signal can be termed as example of intersecting lines

6 0

2 years ago

A sociologist was investigating the ages of grandparents of high school students. From a random sample of 10 high school student

umka2103 [35]

Answer:

$(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908$

$(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308$

So then the confidence interval for the difference of means is given by:

$-8.908 \leq \mu_M -\mu_F \leq 5.308$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_{M}= 69.8$ represent the mean for the age of grandmother

$\bar X_{F}= 71.6$ represent the mean for the age of grandfather

$s_{M}= 8.38$ represent the sample deviation for the age of grandmother

$s_{F}= 6.65$ represent the sample deviation for the age of grandfather

$n_M = n_F= 10$

Solution to the problem

For this case the confidence interval is given by:

$(\bar X_{M} -\bar X_F) \pm t_{\alpha/2} \sqrt{\frac{s^2_M}{n_M} +\frac{s^2_F}{n_F}}$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n_M +n_F-2=10+10-2=18$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,18)".And we see that $t_{\alpha/2}=2.101$