Answer:
285 ft²
Step-by-step explanation:
Hello There!
The figure shown is a composite figure so in order to find the total area we are going to need to split the irregular figure into two regular figures:
A parallelogram with the following dimensions
base = 15
height = 7
and a trapezoid with the following dimensions
base 1 = 11
base 2 = 13 (found by subtracting the height of the parallelogram ( 7 ) from the total height of the composite figure ( 20 ) 20 - 7 = 13 so the length of base 2 is 13 ft)
height = 15
Now that we have identified each dimensions of the two regular figures we need to find the area of each individual figure
For the parallelogram
The area of a parallelogram can simply be found by multiplying the height and the base
So A = 15 * 7
15 * 7 = 105 so the area of the parallelogram is 105 square feet
For the Trapezoid
The area of a trapezoid can be found by using this formula
where a and b = bases and h = height
So using the information that we had found about the trapezoids dimensions we plug in the values
![A=\frac{11+13}{2} 15\\11+13=24\\\frac{24}{2} =12\\12*15=180](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B11%2B13%7D%7B2%7D%2015%5C%5C11%2B13%3D24%5C%5C%5Cfrac%7B24%7D%7B2%7D%20%3D12%5C%5C12%2A15%3D180)
So the area of the trapezoid is 180 square feet
Finally we add the areas of the two regular figures
180 + 105 = 285
so we can conclude that the area of the composite figure is 285 ft²