All categories

3 years ago

PLEASE HELP! Whoever answers correctly will get brainliest

Mathematics

1 answer:

bekas [8.4K]3 years ago

7 0

Answer:

The statement at the top says that the triangles are 'similar'. That means that the corresponding angles are equal, and each pair of corresponding sides have the same ratio. From the 4 and the 8, you can see that each side in the small one is 1/2 the length of the corresponding side in the big one. So the missing sides are 1/2 the length of the 7 and the 12.

You might be interested in

In the equation x/35 = 7, what is the value of x? A. 35 B. 245 C. 7 D. 5

tensa zangetsu [6.8K]

The equation given in the question has one unknown variable in the ofrm of "x" and there is also a single equation. So it can be definitely pointed out that the exact value of the unknown variable "x" can be easily determined. Now let us focus on the equation given in the question.
x/35 = 7
x = 35 * 7
x = 245
So we can find from the above deduction that the value of the unknown variable "x" is 245. The correct option among all the options given in the question is option "B". I hope the procedure is not complicated for you to clearly understand.

8 0

3 years ago

(2/5) to the power of 2

Artemon [7]

Answer:

4/25 or 0.16

Step-by-step explanation:

2/5 ^ 2 = 4/25

2/5 x 2/5 = 4/25 or 0.16

3 0

2 years ago

Read 2 more answers

Write the explicit formula for the geometric sequence. 2, 8, 32, 128, ...

miv72 [106K]

The answer is to the geometric sequence is 512

6 0

3 years ago

Read 2 more answers

Determine what the solution is to the following system? Y=3/4x-1 & y=4/3x-1

vichka [17]

Answer:

(0, -1)

Step-by-step explanation:

There are multiple ways of solving this however- since both equations are already in Y-Intercept form, we will use the "Equal Values Method"

First, since both equations are equal to Y, we can set them equal to each other and solve for X

$\frac{3 }{4} x - 1 = \frac{4}{3} x - 1$

To start, you must eliminate the fraction using a "fraction buster" multiply EVERYTHING by 4 then simplify.

$3x - 4 = 5 \frac{1}{3}x - 4$

Since we still have a fraction, we shall do it one more time. This time we multiply by 3

$9x - 12 = 6 x - 12$

Now, solve how you normally would.

9x = 6x

-6x

3x = 0

X = 0

Now, since we know what X would equal in the solution, we are able to plug in X as 0 in one of our equations. We can choose the first one!

$y = \frac{3}{4} (0) - 1$

Now solve which would lead to y = -1

You have your solution as

(X,Y)

(0,-1)

Hope this helps!

4 0

3 years ago

A water tank is in the shape of a cone.Its diameter is 50 meter and slant edge is also 50 meter.How much water it can store In i

Aneli [31]

To get the most accurate answer possible, we're going to have to go into some unsightly calculation, but bear with me here:

Assessing the situation:

Let's get a feel for the shape of the problem here: what step should we be aiming to get to by the end? We want to find out how long it will take, in minutes, for the tank to drain completely, given a drainage rate of 400 L/s. Let's name a few key variables we'll need to keep track of here:

$V$ - the storage volume of our tank (in liters)
$t$ - the amount of time it will take for the tank to drain (in minutes)

We're about ready to set up an expression using those variables, but first, we should address a subtlety: the question provides us with the drainage rate in liters per second. We want the answer expressed in liters per minute, so we'll have to make that conversion beforehand. Since one second is 1/60 of a minute, a drainage rate of 400 L/s becomes 400 · 60 = 24,000 L/min.

From here, we can set up our expression. We want to find out when the tank is completely drained - when the water volume is equal to 0. If we assume that it starts full with a water volume of $V$ L, and we know that 24,000 L is drained - or subtracted - from that volume every minute, we can model our problem with the equation

$V-24000t=0$

To isolate $t$ , we can take the following steps:

$V-24000t=0\\ V=24000t\\ \frac{V}{24000}=t$

So, all we need to do now to find $t$ is find $V$ . As it turns out, this is a pretty tall order. Let's begin:

Solving for $V$ :

About units: all of our measurements for the cone-shaped tank have been provided for us in meters, which means that our calculations will produce a value for the volume in cubic meters. This is a problem, since our drainage rate is given to us in liters per second. To account for this, we should find the conversion rate between cubic meters and liters so we can use it to convert at the end.

It turns out that 1 cubic meter is equal to 1000 liters, which means that we'll need to multiply our result by 1000 to switch them to the correct units.

Down to business: We begin with the formula for the area of a cone,

$V= \frac{1}{3}\pi r^2h$

which is to say, 1/3 multiplied by the area of the circular base and the height of the cone. We don't know $h$ yet, but we are given the diameter of the base: 50 m. To find the radius $r$ , we divide that diameter in half to obtain r = 50/2 = 25 m. All that's left now is to find the height.

To find that, we'll use another piece of information we've been given: a slant edge of 50 m. Together with the height and the radius of the cone, we have a right triangle, with the slant edge as the hypotenuse and the height and radius as legs. Since we've been given the slant edge (50 m) and the radius (25 m), we can use the Pythagorean Theorem to solve for the height $h$ :

$h^2+25^2=50^2\\ h^2+625=2500\\ h^2=1875\\ h=\sqrt{1875}=\sqrt{625\cdot3}=25\sqrt{3}$

With $h=25\sqrt{3}$ and $r=25$ , we're ready to solve for $V$ :

$V= \frac{1}{3} \pi(25)^2\cdot25\sqrt{3}\\ V= \frac{1}{3} \pi\cdot625\cdot25\sqrt{3}\\ V= \frac{1}{3} \pi\cdot15625\sqrt{3}\\\\ V= \frac{15625\sqrt{3}\pi}{3}$

This gives us our volume in cubic meters. To convert it to liters, we multiply this monstrosity by 1000 to obtain:

$\frac{15625\sqrt{3}\pi}{3}\cdot1000= \frac{15625000\sqrt{3}\pi}{3}$

We're almost there.

Bringing it home:

Remember that formula for $t$ we derived at the beginning? Let's revisit that. The number of minutes $t$ that it will take for this tank to drain completely is:

$t= \frac{V}{24000}$

We have our $V$ now, so let's do this:

$t= \frac{\frac{15625000\sqrt{3}\pi}{3}}{24000} \\ t= \frac{15625000\sqrt{3}\pi}{3}\cdot \frac{1}{24000} \\ t=\frac{15625000\sqrt{3}\pi}{3\cdot24000}\\ t=\frac{15625\sqrt{3}\pi}{3\cdot24}\\ t=\frac{15625\sqrt{3}\pi}{72}\\ t\approx1180.86$

So, it will take approximately 1180.86 minutes to completely drain the tank, which can hold approximately $V= \frac{15625000\sqrt{3}\pi}{3}\approx 28340615.06$ L of fluid.

5 0

3 years ago