What is 15 n-45/5=6 n-9
1 answer:
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The question is incomplete. The complete question is :
A sine function that has an amplitude of 16 units, a period of 5 units,a vertical displacement of 3 units up and a phase shift of 2.5 units left. Graph this function and show each step.
Solution :
The standard form of the sine function is
y = a sin (bx - c) + d
Here given :
Amplitude, a = 16
Period :
⇒
Phase shift :
∴
The vertical displacement : d = 3 units up
Now substituting a, b, c and d values in the standard form gives :
The graph is attached below.
