The jar has 6+5=11 marbles.
We have to find the probability of the following event:
1.We pick a marble from a jar that has 11 marbles in total, 5 of them are red
2.We pick a marble from a jar that has now 10 marbles in total, 4 of them are red (because in the previous step we picked a red marble and did not put it back in the jar)
The probability of the first event is:

The probability of the second event is:

The probability of the both events to happen is:

Answer:
u = 4; v = 18
because this is a parallelogram
=> 2u + 2 = 5u - 10
6 = v/3
<=> 3u = 12
v = 6.3
<=> u = 4
v = 18
Answer:-47
Step-by-step explanation:
1# 11+4=15
2# 15+4=19
3# 19+4=23
4# 23+4=27
5# 27+4=31
6# 31+4=35
7# 35+4=39
8# 39+4=43
9# 43+4=47
REMEBER its negative not positive.
Answers:
Answer for row one: 1
Answer for row two: 11
Answer for row three: 16
Answer for row four: 36
=========================================
Work Shown:
Whatever the x value is, we multiply by 5 and subtract off 14 to get the corresponding y value. This is following the order of operations PEMDAS
------------
If x = 3, then
y = 5*x - 14
y = 5*3 - 14 ..... note how x is replaced with 3
y = 15 - 14
y = 1
This means that when x = 3, the y value is y = 1.
So 1 goes in the box in the first row.
---------------
Repeat for x = 5
y = 5*x - 14
y = 5*5 - 14
y = 25 - 14
y = 11
We have 11 as the second answer.
--------------
Repeat for x = 6
y = 5*x - 14
y = 5*6 - 14
y = 30 - 14
y = 16
The third answer is 16.
--------------
Repeat for x = 10
y = 5*x - 14
y = 5*10 - 14
y = 50 - 14
y = 36
The last answer is 36.