Roe bought a video game in Miami. The game was $30. Miami has a 7% sales tax. How much
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So, h(t) is how far is Daniel's head from the surface of the water, namely the surface itself is when the height is nill, so his head is at the surface and the height of it is just 0, thus h(t) = 0. Namely, what is "t" when h(t) is 0?
clearly the seconds cannot be a negative unit, so is not -3/2.
clearly the seconds cannot be a negative unit, so is not -3/2.
The required distance would be 17.88 units coordinates A(-4,5) and B(12,13) and the horizontal distance is 16 units and the vertical distance is 8 units from A to B which are determined by the graphing method.
<h3>What is the distance between two points?</h3>The distance between two points is defined as the length of the line segment between two places representing their distance.
Given AB with coordinates A(-4,5) and B(12,13).
The formula of the distance between two points is A(x₁, y₁) and B(x₂, y₂) is given by: d (A, B) = √ (x₂ – x₁)² + (y₂ – y₁) ².
x₁ = -4, y₁ = 5
x₂ = 12, y₂ = 13
distance = √ (12 – (-4))² + (13 – 5)²
distance = √ (12 + 4)² + (8)²
distance = √ (16)² + (8)²
distance = √ (256 + 64)
distance = √320
distance = 17.88 units
The horizontal distance is 16 units and the vertical distance is 8 units from A to B which are determined by the graphing method.
Learn more about the distance between two points here:
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Answer:
Probability that the sample average is at most 3.00 = 0.98030
Probability that the sample average is between 2.65 and 3.00 = 0.4803
Step-by-step explanation:
We are given that the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65 and standard deviation 0.85.
Also, a random sample of 25 specimens is selected.
Let X bar = Sample average sediment density
The z score probability distribution for sample average is given by;
Z = ~ N(0,1)
where, = population mean = 2.65
= standard deviation = 0.85
n = sample size = 25
(a) Probability that the sample average sediment density is at most 3.00 is given by = P( X bar <= 3.00)
P(X bar <= 3) = P( <=
) = P(Z <= 2.06) = 0.98030
(b) Probability that sample average sediment density is between 2.65 and 3.00 is given by = P(2.65 < X bar < 3.00) = P(X bar < 3) - P(X bar <= 2.65)
P(X bar < 3) = P( <
) = P(Z < 2.06) = 0.98030
P(X bar <= 2.65) = P( <=
) = P(Z <= 0) = 0.5
Therefore, P(2.65 < X bar < 3) = 0.98030 - 0.5 = 0.4803 .