8x-8...............I think so if it’s distributed
Answer:

Step-by-step explanation:

She did not multiply both sides of the equation by 2.
2x-6y =-2
<u>+ 2x+6y=3
</u><u /> 4x =1
x=1/4
y=5/12
Answer:
62.4
Step-by-step explanation:
1/3*5.2*4.5*8=62.4
Answer:
∠B and ∠F
∠F and ∠E . . . already listed in the problem statement, so may not be considered an "other pair"
Step-by-step explanation:
∠C and ∠F are vertical angles, so are congruent. Then any angle complementary to one of those will also be complementary to the other.
Likewise, ∠B and ∠E are vertical angles and congruent. Any angle complementary to one of them will also be complementary to the other. Here, ∠E and ∠F are listed as complementary, so we know ∠B and ∠F will be also.