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ruslelena [56]
3 years ago
7

Write the equation of a line that includes the point (-4,0) and a slope of 3/5 in slope intercept form?

Mathematics
1 answer:
kvasek [131]3 years ago
5 0
The answer is:  " y = (3/5)x <span>−</span> 4 " .
_______________________________________________________
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In the diagram, how many circles are there for each square?<br> DA 1
Lemur [1.5K]

Answer:

Where is the figure or picture

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3 years ago
Which graphs below represent an exponential function? Select all that apply.
Troyanec [42]
The two graphs in the second picture are the graphs of exponential functions. You can detect it from the L shaped graphs. 

The very first graph represents a linear function. A straight line always represents a linear function. In a Linear function, the change in the values of y is constant throughout in relative to change in x values.

The final graph represents a quadratic function rising on both ends. 

Therefore, option b and c are the correct answers
8 0
3 years ago
Read 2 more answers
Polynomial add or subtract (-2x^2-4x+13)+(12x^2+2x-25)
BigorU [14]

1.Simplify.

-2{x}^{2}-4x+13+12{x}^{2}+2x-25−2x2−4x+13+12x2+2x−25

2.Collect like terms.

(-2{x}^{2}+12{x}^{2})+(-4x+2x)+(13-25)(−2x2+12x2)+(−4x+2x)+(13−25)

3.Simplify.

10{x}^{2}-2x-1210x2−2x−12

6 0
3 years ago
An adult brain is about 140 mm wide and divided into two sections (called "hemispheres" although the brain is not truly spherica
Sedbober [7]

Answer: 3.61×10^5 A

Step-by-step explanation: Since the brain has been modeled as a current carrying loop, we use the formulae for the magnetic field on a current carrying loop to get the current on the hemisphere of the brain.

The formulae is given below as

B = u×Ia²/2(x²+a²)^3/2

Where B = strength of magnetic field on the axis of a circular loop = 4.15T

u = permeability of free space = 1.256×10^-6 mkg/s²A²

I = current on loop =?

a = radius of loop.

Radius of loop is gotten as shown... Radius = diameter /2, but diameter = 65mm hence radius = 32.5mm = 32.5×10^-3 m = 3.25×10^-2m

x = distance of the sensor away from center of loop = 2.10 cm = 0.021m

By substituting the parameters into the formulae, we have that

4.15 = 1.256×10^-6 × I × (3.25×10^-2)²/2{(0.021²) + (3.25×10^-2)²}^3/2

4.15 = 13.2665 × 10^-10 × I/ 2( 0.00149725)^3/2

4.15 = 1.32665 ×10^-9 × I / 2( 0.000058)

4.15 × 2( 0.000058) = 1.32665 ×10^-9 × I

I = 4.15 × 2( 0.000058)/ 1.32665 ×10^-9

I = 4.80×10^-4 / 1.32665 ×10^-9

I = 3.61×10^5 A

3 0
3 years ago
Tap A fills 10/11 of a bottle in a minute. Tap B fills 3 4/5 times as many bottles as Tap A in a minute. Find the number of bott
Lunna [17]

Answer:

Tap B fills 4/5 in a minute.

Step-by-step explanation:

3 4/5-10/11

14/5-10/11=4/5

5 0
3 years ago
Read 2 more answers
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