The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
Form the ratio 560/2800 and then mult. the result by 100%:
560
--------- * 100% = 20%
2800
Answer:
32/9
Step-by-step explanation:
2 to the fifth power is 32. 3 to the second power is 9.
Answer: x = 3, y = 3.
Step-by-step explanation:
The decision on a photo
Answer:
<u>A = πR^2</u>
Step-by-step explanation:
<h3>Please refer to the attachment for explanation.</h3>
