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Darya [45]
3 years ago
9

Is this relation a function by using straight line test

Mathematics
1 answer:
Drupady [299]3 years ago
6 0

Answer:

No

Step-by-step explanation:

Graph all points. They do not make a line.

You might be interested in
A father's age is thrice the sum of the ages of his two children. After five years, his age will be
jenyasd209 [6]

Answer: 45 years old

Step-by-step explanation:

<u>Given:</u>

- Father's age is thrice the sum of ages of his two children

- After five years, his age will be twice the sum of their ages

Let x be the two children's current age and 3x be the father's current age

<u>Solve:</u>

Set equation

3x + 5 = 2 ( x + 10 )

Expand parenthesis

3x + 5 = 2x + 20

Subtract 5 on both sides

3x + 5 - 5 = 2x + 20 - 5

3x = 2x + 15

Subtract 2x on both sides

3x - 2x = 15

x = 15

15 × 3 = 45 years old

Hope this helps!! :)

Please let me know if you have any questions

4 0
2 years ago
Three even numbers sum up to 162. the smallest is half the largest and the middle number is 3/4 the largest. what are the three
Scrat [10]
Lets name the largest number as x 
smallest number is half the largest , therefore its x/2 = 0.5x
then middle number is 3/4 the largest , therefore its 3/4x = 0.75x
the sum of the three numbers are 162
the three numbers added are 
x + 0.5x + 0.75x = 162
2.25 x = 162
x = 72
the largest number is 72
then middle number 0.75 x = 0.75 x 72 = 54
smallest number is 0.5x = 0.5 x 72 = 36
answer is  -   36,54,72
3 0
3 years ago
The author drilled a hole in a die and filled it with a lead​ weight, then proceeded to roll it 199 times. Here are the observed
Anton [14]

Answer with explanation:

An Unbiased Dice is Rolled 199 times.

Frequency of outcomes 1,2,3,4,5,6 are=28​, 29​, 47​, 40​, 22​, 33.

Probability of an Event

      =\frac{\text{Total favorable Outcome}}{\text{Total Possible Outcome}}\\\\P(1)=\frac{28}{199}\\\\P(2)=\frac{29}{199}\\\\P(3)=\frac{47}{199}\\\\P(4)=\frac{40}{199}\\\\P(5)=\frac{22}{199}\\\\P(6)=\frac{33}{199}\\\\\text{Dice is fair}\\\\P(1,2,3,4,5,6}=\frac{33}{199}

→→→To check whether the result are significant or not , we will calculate standard error(e) and then z value

1.

(e_{1})^2=(P_{1})^2+(P'_{1})^2\\\\(e_{1})^2=[\frac{28}{199}]^2+[\frac{33}{199}]^2\\\\(e_{1})^2=\frac{1873}{39601}\\\\(e_{1})^2=0.0472967\\\\e_{1}=0.217478\\\\z_{1}=\frac{P'_{1}-P_{1}}{e_{1}}\\\\z_{1}=\frac{\frac{33}{199}-\frac{28}{199}}{0.217478}\\\\z_{1}=\frac{5}{43.27}\\\\z_{1}=0.12

→→If the value of z is between 2 and 3 , then the result will be significant at 5% level of Significance.Here value of z is very less, so the result is not significant.

2.

(e_{2})^2=(P_{2})^2+(P'_{2})^2\\\\(e_{2})^2=[\frac{29}{199}]^2+[\frac{33}{199}]^2\\\\(e_{2})^2=\frac{1930}{39601}\\\\(e_{2})^2=0.04873\\\\e_{2}=0.2207\\\\z_{2}=\frac{P'_{2}-P_{2}}{e_{2}}\\\\z_{2}=\frac{\frac{33}{199}-\frac{29}{199}}{0.2207}\\\\z_{2}=\frac{4}{43.9193}\\\\z_{2}=0.0911

Result is not significant.

3.

(e_{3})^2=(P_{3})^2+(P'_{3})^2\\\\(e_{3})^2=[\frac{47}{199}]^2+[\frac{33}{199}]^2\\\\(e_{3})^2=\frac{3298}{39601}\\\\(e_{3})^2=0.08328\\\\e_{3}=0.2885\\\\z_{3}=\frac{P_{3}-P'_{3}}{e_{3}}\\\\z_{3}=\frac{\frac{47}{199}-\frac{33}{199}}{0.2885}\\\\z_{3}=\frac{14}{57.4279}\\\\z_{3}=0.24378

Result is not significant.

4.

(e_{4})^2=(P_{4})^2+(P'_{4})^2\\\\(e_{4})^2=[\frac{40}{199}]^2+[\frac{33}{199}]^2\\\\(e_{4})^2=\frac{3298}{39601}\\\\(e_{4})^2=0.06790\\\\e_{4}=0.2605\\\\z_{4}=\frac{P_{4}-P'_{4}}{e_{4}}\\\\z_{4}=\frac{\frac{40}{199}-\frac{33}{199}}{0.2605}\\\\z_{4}=\frac{7}{51.8555}\\\\z_{4}=0.1349

Result is not significant.

5.

(e_{5})^2=(P_{5})^2+(P'_{5})^2\\\\(e_{5})^2=[\frac{22}{199}]^2+[\frac{33}{199}]^2\\\\(e_{5})^2=\frac{1573}{39601}\\\\(e_{5})^2=0.03972\\\\e_{5}=0.1993\\\\z_{5}=\frac{P'_{5}-P_{5}}{e_{5}}\\\\z_{5}=\frac{\frac{33}{199}-\frac{22}{199}}{0.1993}\\\\z_{5}=\frac{11}{39.6610}\\\\z_{5}=0.2773

Result is not significant.

6.

(e_{6})^2=(P_{6})^2+(P'_{6})^2\\\\(e_{6})^2=[\frac{33}{199}]^2+[\frac{33}{199}]^2\\\\(e_{6})^2=\frac{2178}{39601}\\\\(e_{6})^2=0.05499\\\\e_{6}=0.2345\\\\z_{6}=\frac{P'_{6}-P_{6}}{e_{6}}\\\\z_{6}=\frac{\frac{33}{199}-\frac{33}{199}}{0.2345}\\\\z_{6}=\frac{0}{46.6655}\\\\z_{6}=0

Result is not significant.

⇒If you will calculate the mean of all six z values, you will obtain that, z value is less than 2.So, we can say that ,outcomes are not equally likely at a 0.05 significance level.

⇒⇒Yes , as Probability of most of the numbers that is, 1,2,3,4,5,6 are different, for a loaded die , it should be equal to approximately equal to 33 for each of the numbers from 1 to 6.So, we can say with certainty that loaded die behaves differently than a fair​ die.

   

8 0
3 years ago
Find the distance between the points (-5, 0) and (-4, 1).
choli [55]
The formula of a distance between two points A and B is : 

AB=\sqrt{(x_{B}- x_{A})^2 +( y_{B}- y_{A})^2     }

You should this formula by heart.

Then, you just have to apply it ! :D

Here :

x_{A}=-5
y_{A} =0

x_{B} =-4
y_{B}= 1

Therefore :

\sqrt{(-4-(-5))^2+(1-0)^2}
=  \sqrt{1^2+1^2}
= \sqrt{1+1}
= \sqrt{2}

In short, the answer would be the first option : \sqrt{2}.

Hope this helps !

Photon

6 0
3 years ago
Read 2 more answers
SOMEONE PLEASE HELP!!!Which of the following represents the synthetic division form of the long
UkoKoshka [18]

Answer:

Choice C

Step-by-step explanation:

When setting up synthetic division you do:

x-5=0

x=5

and get the numerator's coefficients:

1, -3, 4

                   

so that's 5 | 1 -3 4

7 0
2 years ago
Read 2 more answers
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