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3 years ago

Write -1/9 + 10x - 2x^3 + x^5 - x ^4 in standard form

Mathematics

2 answers:

matrenka [14]3 years ago

5 0

X^5 - x^4 - 2x^3 + 10x - 1/9 is the standard form

vlada-n [284]3 years ago

4 0

x^5-x^4-2x^3+10x-1/9

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The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

Viefleur [7K]

Answer:

The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

Suppose a sample of 1537 tenth graders is drawn. Of the students sampled, 1184 read above the eighth grade level. So 1537 - 1184 = 353 read at or below this level. Then

$n = 1537, \pi = \frac{353}{1537} = 0.2297$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2297 - 1.96\sqrt{\frac{0.2297*0.7703}{1537}} = 0.2087$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2297 + 1.96\sqrt{\frac{0.2297*0.7703}{1537}} = 0.2507$

The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).

7 0

3 years ago

PLEASE HELP WILL GIVE BRAINLIEST

Mars2501 [29]

Answer:

f(-2)=4+6+2

f(-2)=12

Step-by-step explanation:

Add -2 where all the x values are then solve

4 0

3 years ago

The area of a square is 75 inches squared. A student correctly wrote the length of each side of the square as a√3. What is the v

aev [14]

Answer: 5 in.

Step-by-step explanation:

Given

The area of the square is $75\ in.^2$

The side length of the square is $a\sqrt{3}$

Area of square $=(\text{length})^2$

$\therefore 75=(a\sqrt{3})^2\\\Rightarrow 75=3a^2\\\Rightarrow a^2=25\\\Rightarrow a=5\ in.$

Thus, value of a is 5 inch

6 0

3 years ago

Characterstics of functions in math

8090 [49]

A function is a relation in which each possible input value leads to exactly one output value

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3 years ago

Help please I ain't very good at math

ruslelena [56]

the idea of showing that multiplying by 1 is true because as long as A and B follow the same ratio pattern (ie. 1n:2n is the same as 2n:4n) the statement will always be true

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3 years ago

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