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3 years ago

A easy question so you get points.

Mathematics

2 answers:

Doss [256]3 years ago

7 0

Answer:

This recent election its Biden.....

lol thx

Follow me!!!!

Jobisdone [24]3 years ago

7 0

Answer:

Biden Harris

Step-by-step explanation:

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Erica plotted the three towns closest to her house on a graph with town AA at (9, 12), town BB at (9, 7) and town CC at (1, 1).

Sliva [168]

To compute the distance between the points, we can apply the distance formula as shown below.

$d = \sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2} }$

In which x₁ and x₂ are the x-coordinates and y₁ and y₂ are the y-coordinates of the two points. Thus, applying this with the segments AABB, AACC, and BBCC, we have

$\overline{AABB} = \sqrt{(9-9)^{2} + (12-7)^{2}} = 5$
$\overline{AACC} = \sqrt{(9-1)^{2} + (12-1)^{2}} = \sqrt{185}$
$\overline{BBCC} = \sqrt{(9-1)^{2} + (7-1)^{2}} = 10$

Now that we have the lengths of all the sides of ΔAABBCC, we can find the missing angles using the Law of Cosines.

Generally, we have

$c^{2} = a^{2} + b^{2} - 2abcosC$

or

$C = cos^{-1} (\frac{a^{2} + b^{2} - c^{2}}{2ab})$

Hence, we have

$\angle AA = cos^{-1} (\frac{(\sqrt{185})^{2} + 5^{2} - 10^{2}}{2(5)(\sqrt185)})$
$\angle BB= cos^{-1} (\frac{5^{2} + 10^{2} - (\sqrt{185})^{2}}{2(5)(10)})$
$\angle CC= cos^{-1} (\frac{10^{2} + (\sqrt{185})^{2} - 5^{2}}{2(5)(\sqrt{185})})$

Simplifying this, we have

$\angle AA = 36.03^{0}$
$\angle BB = 126.87^{0}$
$\angle CC = 17.10^{0}$

Thus, from this, we can arrange the angles from smallest to largest: ∠CC, ∠AA, and ∠BB.

Answer: ∠CC, ∠AA, and ∠BB

3 0

3 years ago

Please solve as soon as possible thank you I appreciate it!

yKpoI14uk [10]

A. 30=3x+6? B. I really can’t figure it out so sorry

7 0

3 years ago

Volume of a cylinder with radius r and height h is

Airida [17]

Answer:

$h = \frac{v}{\pi r^{2} }$

Step-by-step explanation:

7 0

3 years ago

2x-y=-6 3x-4y=-4 Solve using elimination and then substitution

Alinara [238K]

Okay, so first you are going to decide whether to solve for x or solve for y. I am going to solve for x. In order to do so, you must get x by itself.
$2x-y=-6$
$2x=y-6[ [tex]3x-4y=-4$
$3x=4y-4 \\ x= \frac{4y-4}{3}$
The next step is to set both equations equal to each other in order to find y.
\frac{y- $\frac{y-6}{2}= \frac{4y-4}{3} \\ 3(y-6)=2(4y-4) \\ 3y-18=8y-8 \\ -10=5y \\ y=-2$ 6}{2} [/tex]

So now you know that y=-2. The next part is substitution. All you have to do is pick on of the equations and plug in the y value to get the x value.

So your answer to the question is (-4,-2). I hope I've helped you understand how to solve these types of problems. If you have any questions, don't hesitate to ask.

6 0

3 years ago

What is 3 to the power of 4 simpifyed

Lena [83]

=3*3*3*3
=3^4
=81

81 is the answer

5 0

3 years ago

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