You distribute. First 3,000* 7.Then 600 *7. Then 40*7. Then 9 AM. Add it up Hopefully this helps
Tbh I forgot :)
Answer:
If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.
Step-by-step explanation:
Here in this question, we want to state what will happen if the null hypothesis is true in a chi-square test.
If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.
This is because at a higher level of discrepancies, there will be a strong evidence against the null. This means that it will be rare to find discrepancies if null was true.
In the question however, since the null is true, the discrepancies we will be expecting will thus be small and common.
Answer: V = (10.4 mph, 38.6 mph)
Step-by-step explanation:
The velocity is written as (vx, vy)
where vx is the component of the velocity in the x-axis and vy is the component of the velocity in the y-axis.
In usual notation, the angles are measured counterclockwise from the positive x-axis.
We know that the angle is 75°, this means that the velocity in the x-axis will be equal to the total velocity of the bird projected in the x-axis (suppose a triangle rectangle, where the velocity is the hypotenuse, the x component is a cathetus and the y component is other cathetus)
vx = 40mph*cos(75°) = 10.4 mph
vy = 40mph*sin(75°) = 38.6mph
Then the vector of velocity is V = (10.4 mph, 38.6 mph)
Answer:
1:3 ............... ......
