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kiruha [24]
3 years ago
6

Which statement would be true if you evaluate the expression 18x (365x12)

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
4 0

Answer:

c. the solution is 3 times as large as 6x(365x12)

Step-by-step explanation:

c. the solution is 3 times as large as 6x(365x12)

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Find the measures of the angles of an isosceles triangle with a vertex angle of 42 degrees
I am Lyosha [343]

Answer:

69°, 69°, and 42°

Step-by-step explanation:

Isosceles triangles have three angles -- one vertex angle and two base angles.

The <u>base angles have the same measure</u> and the vertex angle has a different measure.

<u>Remember all triangles' interior angles sum to 180°.</u>

If the vertex angle is 42°, then the two base angles combined are:

180° - 42° = 138°

Since the base angles are the same, <u>each base angle is:</u>

138° ÷ 2 = 69°

Therefore the angles in the triangle measure 69°, 69°, and 42°.

3 0
4 years ago
Evaluate the line integral ∫cf⋅dr, where f(x,y,z)=5xi−4yj+3zk and c is given by the vector function r(t)=⟨sint,cost,t⟩, 0≤t≤3π/2
Katena32 [7]

WIth the parameterization

\mathbf r(t)=\langle\sin t,\cos t,t\rangle

we end up with

\mathbf f(\mathbf r(t))=\mathbf f(\sin t,\cos t,t)=5\sin t\,\mathbf i-4\cos t\,\mathbf j+3t\,\mathbf k

We also have

\mathrm d\mathbf r=\mathbf r'(t)\,\mathrm dt=\langle\cos t,-\sin t,1\rangle\,\mathrm dt

So in the line integral, we get

\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=0}^{t=3\pi/2}\mathbf f(\mathbf r(t))\cdot\mathbf r'(t)\,\mathrm dt

=\displaystyle\int_{t=0}^{t=3\pi/2}(9\sin t\cos t+3t)\,\mathrm dt=\frac98(3\pi^2+4)

8 0
3 years ago
5+4g+8=1 (g=-3;g=-1;g=2)
DochEvi [55]
Hello : 
<span>5+4g+8=1
g = -3 : 5+4(-3)+8 = 13-12 = 1  ... right</span>
3 0
3 years ago
Benjamin is trying to find the height of a radio antenna on the roof of a local building.
xz_007 [3.2K]

The height of the antenna on the roof of the local building is approximately 8 meters.

The situation forms a right angle triangle.

<h3>Properties of a right angle triangle:</h3>
  • One of its angles is equals to 90 degrees
  • The sides of the triangles can be calculated using Pythagoras theorem.

Therefore, let's find the height of the building and the radio antenna from the eye point.

Using trigonometric ratios,

tan 40° = opposite / adjacent

tan 40° = x / 25

where

x = the height of the building and the radio antenna from the eye point.

x = 25 tan 40

x = 25 × 0.83909963117

x = 20.9774907794 meters

Let's find the height of the building from his eye point.

tan 28° = y / 25

where

y = height of the building from his eye point

y = 25 × tan 28°

y = 25 × 0.53170943166

y = 13.2927357915 meters

Height of the antenna = 20.9774907794 - 13.2927357915 = 7.68475498786

Height of the antenna ≈ 8 meters

learn more on elevation here: brainly.com/question/17582385?referrer=searchResults

8 0
3 years ago
Help PLEASE im stucckkkk!!!
noname [10]

Answer:

Surface area of the cube = 150\ cm^2

Step-by-step explanation:

Given shape in figure 1:

Cube with edge length = 5 cm

To find the surface area of the cube.

Solution:

The surface area of a cube is given by the formula:

Surface\ Area = 6a^2

where a represents the length of the edges of the cube.

For the given cube a=5\ cm

Plugging a=5\ cm in the formula to find the surface area of the cube.

Surface\ Area = 6(5)^2

∴ Surface\ Area = 6\times 25 = 150\ cm^2

8 0
4 years ago
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