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Jet001 [13]
3 years ago
12

(4,-2) and (-4,-4) slope= y-intercept= slope intercept equation=

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
7 0

Answer:

Slope: 1/4

Y intercept: (0,-3)

Slope intercept equation: y= 1/4x - 3

Step-by-step explanation:

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The fuel tank of a certain airplane can hold up to 300 gallons of fuel. Let W be the total weight of the airplane (in pounds). L
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35

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3 years ago
Lori wants to determine the average amount of time that students at her school spend on a computer each day there are 350 studen
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Answer:

2 students from each 15 classrooms

Step-by-step explanation:

"The number of boys and girls is approximately equal" is probably the most random sample, that is if the whole topic of the publication is Lorrie and her experimenting endeavors. If that is not the subject, then "Lorrie wants to determine the average amount of time that students at her school spend on the computer each day" is the most strange and random

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3 years ago
Which line is most likely to have a slope of 10 ?
hodyreva [135]
The line that is most likely to have a slope of 10 is the second one down
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3 years ago
Read 2 more answers
Solve for x. Thank you.
Bas_tet [7]

Answer:

D) 50/3

Step-by-step explanation:

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6/10 = 10/x

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4 0
3 years ago
In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p
Alenkinab [10]

Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is  \frac{23}{30} or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

P(A \cup B)=P(A)+P(B)-P(A \cap B)---------------(1)

where

P(A) = Probability of choosing  a student playing basket ball

P(B) =  Probability of choosing  a student playing base ball

P(A \cap B) =  Probability of choosing  a student playing both the games

<u>Finding  P(A)</u>

P(A) = \frac{\text { Number of students playing basket ball }}{\text{Total number of students}}

P(A) = \frac{19}{30}--------------------------(2)

<u>Finding  P(B)</u>

P(B) = \frac{\text { Number of students playing baseball }}{\text{Total number of students}}

P(B) = \frac{12}{30}---------------------------(3)

<u>Finding P(A \cap B)</u>

P(A) = \frac{\text { Number of students playing both games }}{\text{Total number of students}}

P(A) = \frac{8}{30}-----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}

P(A \cup B)= \frac{31}{30} -\frac{8}{30}

P(A \cup B)= \frac{23}{30}

7 0
3 years ago
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