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slega [8]
3 years ago
7

Nathaniel mowed 18 lawns in 3 hours. What was his rate of mowing in hours per lawn?

Mathematics
1 answer:
inna [77]3 years ago
8 0
The answer is 6 lawns per hour
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Subtract. 5x^2-5x+1-(2x^2+9x-6)
Talja [164]
<h2>Hello!</h2>

The answer is:

3x^{2} -14x+7

<h2>Why?</h2>

To solve the problem we need to add/subtract like terms. We need to remember that like terms are the terms that share the same variable and the same exponent.

For example, we have:

x^{2} +2x+3x=x^{2} +(2x+3x)=x^{2}+5x

We have that we were able to add just the terms that were sharing the same variable and exponenr (x for this case).

So, we are given the expression:

5x^2-5x+1-(2x^2+9x-6)=5x^{2}-2x^{2}-5x-9x+1-(-6)\\\\(5x^{2}-2x^{2})+(-5x-9x)+(1-(-6))=3x^{2}-14x+7

Hence, the answer is:

3x^{2} -14x+7

Have a nice day!

4 0
3 years ago
Find the f^-1(x) and it’s domain
borishaifa [10]

Answer:

f^{-1}(x) = (x + 8)^2

x \ge -8

Step-by-step explanation:

Given

f(x) = \sqrt x - 8

Solving (a): f^{-1}(x)

We have:

f(x) = \sqrt x - 8

Express f(x) as y

y = \sqrt x - 8

Swap x and y

x = \sqrt y - 8

Add 8 to both\ sides

x + 8 = \sqrt y - 8 + 8

x + 8 = \sqrt y

Square both sides

(x + 8)^2 = y

Rewrite as:

y = (x + 8)^2

Express y as: f^{-1}(x)

f^{-1}(x) = (x + 8)^2

To determine the domain, we have:

The original function is f(x) = \sqrt x - 8

The range of this is: f(x) \ge -8

The domain of the inverse function is the range of the original function.

<em>Hence, the domain is:</em>

x \ge -8

3 0
3 years ago
.....................................
Mandarinka [93]

\frac{5}{a + 3} = \frac{3}{a - 2}

5(a - 2) = 3(a + 3)

5a - 10 = 3a + 9

5a - 3a = 9 + 10

2a = 19

a = \frac{19}{2} = 9 \frac{1}{2}

Answer = D.) a = 9 \frac{1}{2}

\textbf{Spymore}​

4 0
3 years ago
Please help with this question
puteri [66]
The answer i found to be is C

4 0
2 years ago
Evaluate ab for a = 11 and b = 4. <br><br> a.15 <br> b.44 <br> c.114 <br> d.40
skad [1K]

ab = (11)(4) \\ ab = 44

Answer is B. 44

Hope this helps. - M
7 0
3 years ago
Read 2 more answers
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