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3 years ago

If you have meeting tomorrow at 8:00 with zoom. drop your code

Mathematics

2 answers:

asambeis [7]3 years ago

4 0

Answer:

WHY BIT.CH!!!????????!!!!!!!!!!!! Wait can u come to my engineering zoom.

Step-by-step explanation:

Sidana [21]3 years ago

3 0

Sometimes I don't wanna be happy

Don't hold it against me

If I'm down, just leave me there

Let me be sad

Sun's up, I already wanna lay down

Friends calling, are you really tryna go out? (No)

Don't wanna get dressed up to pretend (no)

I can lie and say I'm fine

Maybe you'll stop calling then

I've got chips on my shoulder

Only getting older

So I keep to myself

Ain't tryna complain

Just don't wanna explain it

But sometimes I don't wanna be happy

Don't hold it against me

If I'm down, just leave me there

Let me be sad

Sometimes I just wanna be lonely

Don't need you to hold me

If I'm low, you don't need to care

Let me be sad

What's the matter with that? (Oh-oh-oh)

What's the matter with-

Bad days, it's okay, let me feel it (uh-huh, uh-huh)

And some days, you've got to break your heart to heal it (heal it)

I know I'm gonna feel this way again

I can lie and say I'm fine

But that wouldn't change anything

I've got chips on my shoulder

Only getting older

So I keep to myself

Ain't tryna complain

Just don't wanna explain it

But sometimes I don't wanna be happy

Don't hold it against me

If I'm down, just leave me there

Let me be sad

Sometimes I just wanna be lonely

Don't need you to hold me

If I'm low, you don't need to care

Let me be sad

What's the matter with that? (Oh-oh-oh)

What's the matter with sadness?

Making me feel the way I feel right now

Goodness

Can't force it when you feel ******** up

It's the salt that's on my tongue

But sometimes I don't wanna be happy

Don't hold it against me

If I'm down, just leave me there

Let me be sad

Sometimes, I just wanna be lonely

Don't need you to hold me

If I'm low, you don't need to care

Let me be sad

What's the matter with that? (Oh, oh, oh)

Just let me be sad

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If the correlation between height and weight of a large group of people is 0.75, find the coefficient of determination (as a

Shtirlitz [24]

Independent variable is the predictor variable which is the height and dependent variable is the response variable which is weight in this scenario.

The square of correlation coefficient gives the coefficient of determination. It is denoted by R² (R squared).

We are given:
R = 0.75

So,
R² = 0.75²

R² = 0.5625

R² = 56.25 %
The coefficient of determination tells how much of the trend of dependent data can be explained by the independent data using the linear regression model. So in the given case, Height can explain 56.25% of the trend in the weight.

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3 years ago

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After conducting a survey of all her classmates, Midge discovers that the amount of money everyone spends buying books each mont

andreyandreev [35.5K]

The mean is the average of the numbers: a calculated "central" value of a set of numbers.

Therefore: If the amount spent on books per month by all her classmates is leveled that amount would be $30

To calculate it: add up all the numbers, then divide by how many numbers there are

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3 years ago

If x= -3, and -3 = y, then what can be said about the relationship between x and y? Explain

ella [17]

I'd say that the relationship between y and x is that they're both equivalent to each other, since -3 = -3.

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3 years ago

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One of the legs of a right triangle measures 9 cm and the other leg measures 11 cm.

ikadub [295]

Answer:

$\boxed {\boxed {\sf 14.2 \ cm}}$

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean Theorem to solve for the sides.

$a^2+b^2=c^2$

where a and b are the legs and c is the hypotenuse. In this triangle, we know the legs are 9 centimeters and 11 centimeters, or:

a= 9 cm
b= 11 cm

Substitute these values into the formula.

$(9 \ cm)^{2} +(11 \ cm)^{2} =c^{2}$

Solve the exponents.

(9 cm)²= 9 cm*9 cm=81 cm²

$81 \ cm^{2} +(11 \ cm)^{2} =c^{2}$

(11 cm)²= 11 cm*11 cm= 121 cm²

$81 \ cm^{2} +121 cm^{2} =c^{2}$

Add the values on the left side.

$202 \ cm^{2} =c^{2}$

Since we are solving for c, we must isolate the variable. It is being squared and the inverse of a square is the square root. Take the square root of both sides.

$\sqrt {202 \ cm^{2} }=\sqrt{c^{2} }$