Answer:
(a) 0.0885 M
(b) 1.25
Step-by-step explanation:
Solute S has a partition coefficient of 5.9 between water (phase 1) and hexane (phase 2).
i.e Partition coefficient Kd = [S(hexane]/[S(water) = 5.9
to calculate the concentration of S in hexane; we have;
[S(hexane]/0.015 = 5.9
[S(hexane)] = 5.9 x 0.015
= 0.0885 M
Question B say ,
If the volume of water is 85.0 mL
and the volume of hexane is 18.0 mL,
to find the quotient (mol S in hexane/mol S in water), we will multiply the
Partition coefficient Kd with volume of hexane divided by volume of water
i.e Partition coefficient Kd = (moles/volume of S in hexane)/(moles/volume of S in water)
∴
(moles of S in hexane/moles of S in water) = Kd x (volume of hexane/volume of water)
= 5.9 x 18.0/85.0
= 1.25
Equation is: 200x + 250y = 3800
Put x = 0
then 250y = 3800
y = 3800 / 250
y = 15.2
Now, Put y = 0
200x = 3800
x = 3800/200
x = 19
So, the coordinates are: (19, 0) & (0, 15.2)
We will mark those coordinates & draw the line from origin. Graph is done
Hope this helps!
Answer: x = 12
Step-by-step explanation:
We can see two triangles rectangles, we will use the angle S to solve this, as this angle is common to both triangles.
We know that:
cos(S) = adj cathetus/hipotenuse.
Then we have, for the triangle SRT.
Cos(S) = 9/SR.
for the big triangle, SQR, we have:
Cos(S) = SR/(9 + 16)
now we can find the quotient of those two equations and get:
cos(S)/cos(S) = 9/Sr*(9+16)/SR
SR^2 = 9*(25)
SR = 15.
Now with this side we can find the value of x.
We can use the Pythagorean theorem in the triangle SRT, where the sum of the squared cathetus is equal to the hypotenuse:
9^2 + x^2 = 15^2
x = √(15^2 - 9^2) = 12
For the answer to the question above, a system of equations has no solution when the lines representing the equation are parallel but do not coincide. For two lines to be parallel, the must have the same gradient i.e. coefficient of x when y is made the subject of formula must be equal.
If one of the equations is
y = 8x + 7,
then the other equation will be
y = 8x - 7
5- -1= 6
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