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3 years ago

F(x)= 3x^2+5x-8. Solve the quadratic equation

Mathematics

1 answer:

7nadin3 [17]3 years ago

7 0

Answer:

$\bold{x_1=1\ ,\quad x_2=-\dfrac83}$

Step-by-step explanation:

$3x^2+5x-8=0\quad\implies\quad a=3\,,\ b=5\,,\ c=-8\\\\x=\dfrac{-5\pm\sqrt{5^2-4(3)(-8)}}{2\cdot3}=\dfrac{-5\pm\sqrt{25+96}}{6}=\dfrac{-5\pm\sqrt{121}}{6}\\\\ x_1=\dfrac{-5+11}{6}=1\ ,\qquad x_2=\dfrac{-5-11}{6}=\dfrac{-16}6=-\dfrac83$

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Find the midpoint of the segment whose endpoints are (8,6) and (-2,-8).

inna [77]

Answer:

$\huge{ \fbox{ \sf{ \: ( \: 3 \: , \: - 1 \: )}}}$

Step-by-step explanation:

$\star{ \sf { \: Let \: the \: points \:be \: A \: and \: B}}$

$\star{ \sf{ \: Let \: \: A (8,6) \: be \: (x1 \:, y1) and \: B(-2,-8) \: be \: (x2 \:, y2)}}$

$\underline{ \sf{Finding \: the \: midpoint}}$

$\boxed{ \rm{Midpoint \: = \: ( \frac{x1 + x2}{2} \: , \: \frac{y1 + y2}{2} )}}$

$\mapsto{ \sf{Midpoint = ( \frac{8 + ( - 2)}{2} \: , \: \frac{6 + ( - 8)}{2} )}}$

$\mapsto { \sf{Midpoint = ( \frac{8 - 2}{2} \: , \: \frac{6 - 8}{2} }})$

$\mapsto{ \sf{Midpoint = ( \frac{6}{2} \: , \: \frac{ - 2}{2}) }}$

$\mapsto{ \sf{Midpoint = (3 \: \: , - 1)}}$

Hope I helped!

Best wishes!! :D

~ $\sf{TheAnimeGirl}$

5 0

3 years ago

Determine the slope from the given graph below:

Greeley [361]

Step-by-step explanation:

the slope is the ratio of "y coordinate difference / x coordinate difference".

so, let's find 2 good points (I mean by that with integer coordinates). I see e.g.

(-1, -1) and (0, -7)

x changes by +1 (from -1 to 0).

y changes by -6 (from -1 to -7).

so, the slope is -6/1 = -6.

D is the right answer.

8 0

2 years ago

I need estimate then record the product

creativ13 [48]

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3 years ago

Find the area of the shaded region. Round to the nearest hundredth where necessary (2 decimal places

suter [353]

Answer:

117 in²

Finding the area of the trapezoid:

First, we need to find the area of the trapezoid formed by the dotted lines. The formula for finding the area of the trapezoid is "(a₁ + a₂)h/2".

[Where, a₁ = shorter parallel side; a₂ = longer parallel side]

⇒ (a₁ + a₂)h/2 = Area of trapezoid

⇒ (14 + 26)15/2 = Area of trapezoid

⇒ Area of trapezoid = (40)15/2 = (20)15 = 300 in²

Reviewing on how to find the area of the unshaded region:

To find the area of the shaded region, we need to subtract the area of the unshaded region from the area of the trapezoid. In this case, the unshaded region is a triangle whose base is 26 inches. To find the area of the triangle, we need to use the formula 1/2 x Base x Height. We are given the base, but the height is unknown.

Determining the height:

We are given a small side length "6 inches" and the height of the trapezoid "15 inches". If we subtract the small side length from the height of the trapezoid, we will obtain the height of the triangle.

⇒ Height of trapezoid - Small side length = Height of triangle

⇒ 15 - 6 = Height of triangle

⇒ 9 in = Height of triangle

Determining the area of the unshaded region:

Now, let's substitute the base and the height in the formula to find the area of the triangle

⇒ 1/2 x Base x Height

⇒ 1/2 x 26 x 9

⇒ 13 x 9

⇒ 117 in²

Determining the area of the shaded region:

Finally, let's subtract the area of the unshaded region from the area of the trapezoid to obtain the area of the shaded region.

⇒ Area of trapezoid - Area of unshaded region = Area of shaded region

⇒ 300 - 117 = Area of shaded region

⇒ 183 in² = Area of shaded region

5 0

2 years ago

Consider the quadratic function f(y) = 8y2 – 7y + 6. What is the constant of the function?

olga55 [171]

For this case we have the following expression:

$f (y) = 8y ^ 2 - 7y + 6$

we observe that we have a polynomial of the second degree.

The constant term of the polynomial, is that coefficient that is not written accompanying a variable.

We have then that the constant term of the quadratic function is:

Answer:

the constant of the function is:

8 0

3 years ago