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shepuryov [24]
3 years ago
5

Find the slope of each line

Mathematics
1 answer:
sammy [17]3 years ago
3 0
The slope is 3/2 or y = 3/2x - 1
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I have a test In math Tommorow and its a make or break situation for my grade I really need help with this question!
irina [24]
I was just in the same situation, you got this. the answer is A.
8 0
4 years ago
Read 2 more answers
Could someone please help me out? I've tried to solve this but I'm really having some trouble with it. Please try to explain it
guajiro [1.7K]

To find the area of the shaded region you need find the area of the shaded region and subtract the area of the unshaded region.

Area of a rectangle = width x length

A = (x + 10) x (2x + 5)

Next apply FOIL or First Outer Inner Last

A = (x * 2x) (x * 5) (10 * 2x) (10 * 5)

A= 2x2 + 5x + 20x + 50

A= 2x2 +25x +50

 

Area of a square=  sides2

A= (x + 1)2

A= (x+1) (x+1)

Next apply FOIL or First Outer Inner Last

A = (x *x) (1*x) (1*x) (1*1)

A = x2 + 1x + 1x +1

A= x2 + 2x +1

 

A= 2x2 +25x +50 - 2x2 +25x +50

A= 50x + 100





4 0
3 years ago
PLSS HELPP BRAINLIEST AND 65 POINTS <br> pls do the graph too
Eddi Din [679]

Answer:

\Large \boxed{ -x+65}

Step-by-step explanation:

Two points are (0, 65) and (10, 55)

Calculate slope <em>m</em>

\displaystyle m=\frac{y_2 - y_1}{x_2 - x_1}

\displaystyle m=\frac{55-65}{10-0}=-1

Use slope-intercept form

y=mx+b

y=-1x+b

<em>b</em>  is the y-intercept, y-intercept is (0,65)

y=-1x+65

5 0
3 years ago
(3x^2+3)(4+x^3) what the polynomial ?
Ludmilka [50]
<span>(3x^2+3)(4+x^3)
=</span><span>12x^2 +3x^5 + 12 + 3x^3
= </span>3x^5 + 3x^3 + 12x^2 + 12
3 0
4 years ago
Part 3: Write the equation of and graph an ellipse.
tensa zangetsu [6.8K]

Answer:

Step-by-step explanation:

The center is halfway between vertices, at (4, -6).

It is also halfway between foci.

:::::

The vertices are vertically aligned, so the parabola is vertical.

General equation for a vertical ellipse:

 (y-k)²/a² + (x-h)²/b² = 1

with

 center (h,k)

 vertices (h,k±a)

 co-vertices (h±b,k)

 foci (h,k±c), c² = a²-b²

Apply your data and solve for h, k, a, and b.

center (h,k) = (4, -6)

h = 4

k = -6

vertices (4,-6±a) = (4,-6±9)

a = 9

foci (4,-6±c) = (4,-6±5√2)

b² = a² - c² = 9² - (5√2)² = 31

b = √31

The equation becomes

 (y+6)²/81 + (x-4)²/31 = 1

:::::

length of major axis = 2a = 18

length of minor axis = 2b = 2√31

8 0
3 years ago
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