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Solnce55 [7]
3 years ago
14

Mary has 32 geraniums and she wants to plant the same number in each pot. if she has 8 pots , how many geraniums should she put

in each pot?
Mathematics
2 answers:
Nana76 [90]3 years ago
5 0
32 / 8 = 4 geraniums in each pot
mote1985 [20]3 years ago
4 0
32 divided by 8 = 4. So, she should put 4 seeds into each pot.
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Mean is adding all the numbers then dividing the answer you go from the numbers.
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Examine this right triangle. A right triangle has a side length of 16 meters and hypotenuse of 20 meters. Which equation can be
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The equation can be used to find the missing leg in the triangle 20^{2} = 16^{2} +a^{2}.

<h3>What is the right triangle?</h3>

A right-angle triangle is a triangle that has a side opposite to the right angle the largest side and is referred to as the hypotenuse.

It is given that a right triangle has a side length of 16 meters and a hypotenuse of 20 meters.

From a Pythagoras theorem

b^{2} = c^{2} +a^{2} \\20^{2} = 16^{2} +a^{2}\\20^{2}-16^{2} =a^{2}\\a^{2} = 20^{2}-16^{2} \\

Thus, the equation can be used to find the missing leg in the triangle 20^{2}-16^{2} =a^{2}.

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Ned started the month with $137.06 in his bank account. Over the course of the month he got 2 paychecks. One for $286.77 and the
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1. Suppose that a theater charges a school group $4.50 per student to show a special film. Suppose that the theater's operating
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The functions I(x) and E(x) of the theatre's income and expenses are illustrations of linear functions.

<h3>The equation of the theatre's income</h3>

The theatre charges $4.50 per student.

Assume the number of students is x, the equation of the theatre's income would be:

I(x) = 4.5x

<h3>The equation of the theatre's expenses</h3>

The theatre expense per student is $1.25, and the operating cost on the staff is $130

The equation of the theatre's expenses would be:

E(x) = 1.25x + 130

<h3>Complete the table</h3>

Using the formulas I(x) = 4.5x and E(x) = 1.25x + 130, the complete table is:

Students, x  0       10        20     30      40      50      60    70

Income, I      0      45        90     135     180    225    270   315

Expenses, E 130  142.5   155    167.5   180   192.5   205  217.5

<h3>The graph of the theatre's income and expenses</h3>

See attachment

<h3>The pattern by which theatre's income and expenses increase</h3>

The functions I(x) and E(x) are linear functions.

So, the pattern with which the functions increase is a linear pattern.

<h3>The number of students when the theatre's income and expenses are equal</h3>

This means that:

I(x) = E(x)

So, we have:

4.5x = 1.25x + 130

Subtract 1.25 from both sides

3.25x = 130

Divide both sides by 3.25

x = 40

Hence, the number of students is 40

<h3>The theatre profit</h3>

This is the difference between the theatre expenses and their income.

So, we have:

P(x) = E(x) - I(x)

This gives

P(x) = 1.25x + 130 - 4.5x

Simplify

P(x) = 130 - 3.25x

<h3>Solution to the inequalities</h3>

We have:

E(x) < 255

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1.25x + 130 < 255

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x < 100 students

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I(x) > 675

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4.5x > 657

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x > 146 students

Hence, the number of students for the inequalities are less than 100 and greater than 146

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