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Serjik [45]
3 years ago
13

Solve the quadratic y = −x^2 + 4x + 1 with steps plz!

Mathematics
1 answer:
frez [133]3 years ago
7 0

Answer:

x = -0.24 or 3.73

Step-by-step explanation:

\frac{-b + \sqrt{b^{2} -4ac } }{2a} (There's supposed to be a ± between '-b' and the square root)

x^{2} + 4x + 1 ( ax^{2} + bx + c )

a = -1 ( there's no number before x^{2} so its 1 )

b = 4

c = 1

Substitute into the quadratic equation.

\frac{-4 + \sqrt{4^{2} -4x1x-1 } }{2x-1} ( the x is just the multiplication sign )

=  \frac{-4 + \sqrt{{16} +4 } }{-2}

\frac{-4 + \sqrt{{20} } }{-2} = -0.24    [OR]     \frac{-4 - \sqrt{{20} } }{-2} = 3.73

( The answers are to 2 decimal places )

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You brought 9 feet of elastic to make hair ties each hair ties need 3 3/8 inches of elastic how many hair ties can you make
PIT_PIT [208]

Answer:

32\ hair\ ties

Step-by-step explanation:

we know that

To make one hair ties is needed 3 3/8 inches of elastic

so

using proportion

Find out how many hair ties can you make with 9 feet of elastic

Remember that

1\ ft=12\ in

Convert 9 ft to inches

9\ ft=9*12=108\ in

Convert mixed number to an improper fraction

3\frac{3}{8}\ in=\frac{3*8+3}{8}=\frac{27}{8}\ in

using proportion

\frac{1}{(27/8)}=\frac{x}{108}\\\\x=108*8/27\\\\x=32\ hair\ ties

3 0
3 years ago
If an original statement is represented by p>q which represents the contrapositive?
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An implication of p→ q, its contrapositive will be:
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In our example the implication p→ q is p>q and is contrapositive is:
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5 0
3 years ago
Simplified quotient of x+8/x^2÷2x+16/2x^2?
sineoko [7]

Answer:

1

Step-by-step explanation:

The exprssion to be simplified is,

\frac{x + 8}{ {x}^{2}}  \div  \frac{2x + 16}{ {2x}^{2} }

=  \frac{x + 8}{ {x}^{2}} \times  \frac{ {2x}^{2} }{2x + 16}

= \frac{ {2x}^{3} +  {16x}^{2} }{{2x}^{3} + {16x}^{2}}

=1

8 0
3 years ago
What is the Gcf of 8x and 40
Naya [18.7K]
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5 0
3 years ago
An arithmetic sequence has a common difference of 5 and the 3rd term is 15. What is the 5th term?
trapecia [35]

Answer:

an=8n−14

Step-by-step explanation:

for an AP

where

a

1

=

the first term

d

=

the common difference

then we have

a

1

,

(

a

1

+

d

)

,

(

a

1

+

2

d

)

,

...

,

a

1

+

(

(

n

−

1

)

d

)

,

.

.

we are given the third term

10

=

a

1

+

2

d

−

−

(

1

)

and the fifth term

26

=

a

1

+

4

d

−

−

(

2

)

subtract

(

2

)

−

(

1

)

16

=

2

d

⇒

d

=

8

sub into

(

1

)

10

=

a

1

+

2

×

8

⇒

a

1

=

−

6

so the nth term

a

n

=

a

+

(

n

−

1

)

will be

a

n

=

−

6

+

8

(

n

−

1

)

a

n

=

8

n

−

14

3 0
2 years ago
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