16) First solve like a normal equation.
3|x/9| - 1 = 2
3|x/9| = 3
|x/9| = 1
Now just separate into two equations:
x/9 = 1
x/9 = -1
So x = 9, -9
17) Solve like normal:
-4 - 2|b - 10| = -6
-2 |b - 10| = -2
|b - 10| = 1
Now just separate into two equations:
b - 10 = 1
b - 10 = -1
So then b = 11, 9
Answer:
Her mistake is that she should plot the point (0, 5) first, not (1, -3)
Step-by-step explanation:
First I simplified the equation given.
y - 3 = 2 (x + 1)
y - 3 = 2x + 2
+3 +3
y = 2x + 5
Since 5 is our y-intercept we would want to graph that first, which would be (0, 5) as a point.
Hope this helps!
The slopes of 2 perpendicular lines with be reciprocals with the opposite sign.
For example if you have the equation y=-5x+2, your slope is -5. In a line perpendicular to y=-5x+2, your slope would be 1/5. As for finding b in y=mx+b for your second equation, I would need more specific information.
Hope it helps!
Answer:
http://collinskarr.weebly.com/uploads/5/7/7/6/57764943/geometrytaskprojectparallellinescityprojectandwritingassignment.pdf
Step-by-step explanation:
i think thes is a life hack thing
i am not a inappropriate robot
