A = xy
A' = xy' +x'y
A' = (13 cm)*(5 cm/s) +(8 cm/s)*(11 cm)
.. = (65 +88) cm^2/s
.. = 153 cm^2/s . . . . . . . the rate at which rectangle area is changing
_____
Check:
.005 seconds before the time of interest, the area was
.. (13 cm -.005*8 cm) * (11 cm -.005*5 cm) = 12.96*10.975 = 142.236 cm^2
.005 seconds after the time of interest, the area is
.. 13.04* 11.025 = 143.766 cm^2
So the average rate of change over that 0.01 second interval is
.. (143.766 -142.236)/(.01) = 153 cm^2/s . . . . close enough
??? Where’s the rest of that problem
Answer:
<h3> the first number is 5</h3><h3> the first second is 6</h3><h3> the first number is 1</h3>
Step-by-step explanation:
x - first number
2x - twice the first number
twice the first number exceeds the second number by 4 so:
2x-4 -the second number
y - the third number
the second number is equal to the sum of the first and third numbers:
2x-4 = x + y
x + y = 2x - 4
-x -x
y = x - 4 - the third number
the sum of three numbers:
x + 2x-4 + x-4 = 4x - 8
The sum of three numbers is 12 so:
4x - 8 = 12
+8 +8
4x = 20
÷4 ÷4
x = 5
2x-4 = 2•5 - 4 = 6
x-4 = 5 - 4 = 1
Check:
5+1 = 6
2•5 = 10, 10-4 = 6
Answer:
#5 has an output of 14. #6 has an output of 32.
Step-by-step explanation:
3(3) +5=y 9+5=y 14=y
3(9) +5=y 27+5=y 32=y
