Sorry I'm late! xx
Okay, so two of the sides in an isosceles triangle are of the same length. The lengths are either in the ratio 5:5:6 or 5:6:6
The perimeter is 32 cm
If we take the first ratio, 5:5:6, then we have 16 "parts". Let the length of each "part" be referred to as "x"
So, 16x = 32, and so x = 2
So, the ratio of the sides are 10 cm, 10 cm, 12 cm.
To find the height, "h", we need to use Pythagoras' Theorem, with 10 being the hypotenuse and 6 being the horizontal side (think of a line cutting straight down the middle of the isosceles triangle)
h^2 + 36 = 100
h = 8 cm
Area of a triangle is 0.5 x base x height. So, 0.5 x 12 x 8 = 48 cm^2
Hope I helped!! xx
The first thing we should know is the area of the triangular base.
Triangular base area:
A1 = root (s * (s-a) * (s-b) * (s-c))
Where, s is the semi-meter of the triangle:
s = (a + b + c) / 2
a, b, c: sides of the triangle.
Substituting:
s = (2 + 3 + 4) /2=4.5
A1 = root (4.5 * (4.5-2) * (4.5-3) * (4.5-4))
A1 = 2.90
Then, you must know the area of each rectangle associated with each side of the triangular base.
Rectangle area 1:
Ar1 = (a) * (l)
Ar1 = (2) * (7)
Ar1 = 14
Rectangular area 2:
Ar2 = (b) * (l)
Ar2 = (3) * (7)
Ar2 = 21
Rectangular area 3:
Ar3 = (a) * (l)
Ar3 = (4) * (7)
Ar3 = 28
Finally the surface area is:
A = Ar1 + Ar2 + Ar3 + 2 * A1
A = (14) + (21) + (28) + 2 * (2.90)
A = 68.8 in ^ 2
answer:
<span> the surface area of the box of chocolates is
</span> A = 68.8 in ^ 2
Answer:
Choice B. only Shota
Step-by-step explanation:
16z^2 - 40z
the greatest common value is 8z
8z (2z^2 -5)
24z^2 - 40z
the greatest common value is 8z
8z (3z^2 -5)
8z / 8z = 1
= 
x 
= 1 x = (Shota)
A. (-1.15)×3.2 = -(1.15×(3 + .2))
... = -(1.15×3 + 1.15×.2) = -(3.45 + 0.23)
... = -3.68
B. There are two factors in the product, one of which is negative. The total number of negative factors is an odd number, so the product will be negative.
You can also enter the numbers with their signs into a calculator, and it will correctly calculate the sign of the product.
