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olga55 [171]
3 years ago
11

Help! What’s the answer.. It’s a Khan Academy Problem

Mathematics
1 answer:
mote1985 [20]3 years ago
4 0

Answer:

Choice B. only Shota

Step-by-step explanation:

16z^2 - 40z

the greatest common value is 8z

8z (2z^2 -5)

24z^2 - 40z

the greatest common value is 8z

8z (3z^2 -5)

\frac{8z (2z^2 -5)}{8z (3z^2 -5)}

8z / 8z = 1

= \frac{8z}{8z} x \frac{2z^2 -5}{3z^2 -5} = 1 x \frac{2z^2 -5}{3z^2 -5} = \frac{2z^2 -5}{3z^2 -5} (Shota)

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<h3>Calculating density </h3>

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