Answer:
Perron–Frobenius theorem for irreducible matrices. Let A be an irreducible non-negative n × n matrix with period h and spectral radius ρ(A) = r. Then the following statements hold. The number r is a positive real number and it is an eigenvalue of the matrix A, called the Perron–Frobenius eigenvalue.
<span>The hypothesis is : If Robbie wants to save money to buy a car. Conclusion : he must get a part-time job.
Robbie already started the new job yesteday. So, that makes the hypothesis true.
So, the conclusion would be : Robbie will save money to buy a car/ Robbie will buy a car.</span>
Answer:
a) (2+8)+9
b) (3+7)+5+4
c) (4+16)+2
d) (31+9)+4
Step-by-step explanation:
a) 2+9+8
2 and 8 add up to 10, so we regroup them in parentheses
(2+8)+9
b) 3 + 5 + 4 + 7
3 and 7 add up to 10, so we regroup them in parentheses
(3+7)+5+4
c) 4 + 2 + 16
4 and 16 add up to 20 which is a multiple of 10, so we regroup them in parentheses
(4+16)+2
d) 31 + 4 + 9
31 and 9 add up to 40 which is a multiple of 10, so we regroup them in parentheses
(31+9)+4
Answer:
well the money doubles every 6 years but its only been 4 so
7,400 x 4 = 29,600
$29,600 is the answer
D because it says you will be getting at least 4500 or more dollars by adding the adult and student tickets
