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2 years ago

What is 10% less than 220?

Mathematics

1 answer:

qaws [65]2 years ago

3 0

Answer:

198

Step-by-step explanation:

10% less of 220

=> 220 - 10% of 220

=> 220 - (10/100 × 220)

=> 220 - 22

=> 198

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The length of giselles arm is 27 inches.The length of her lower arm is 17 inches.About what percent of giselles arm is her lower

elena-s [515]

27 divided by 100 is 0.27 so 0.27 is one percent now 17 divided by 0.27 is about 62.963 so 17 is 62.963% of 27 hope this helped.

6 0

2 years ago

Evaluate the limit of lim/n->infinity 6n^2+5/3n^2

castortr0y [4]

we are given

$\lim_{n \to \infty} \frac{6n^2+5}{3n^2}$

we can see that

degree of numerator = degree of denominator =2

so, we can divide both numerator and denominator by n^2

and we get

$\lim_{n \to \infty} \frac{(6n^2+5)/n^2}{(3n^2/n^2)}$

$\lim_{n \to \infty} \frac{(6n^2/n^2)+(5/n^2)}{(3n^2/n^2)}$

now, we can simplify it

$\lim_{n \to \infty} \frac{6+(5/n^2)}{3}$

now, we can plug n=inf

$= \frac{6+(5/(\infty))}{3}$

$= \frac{6+0}{3}$

$= \frac{6}{3}$

$= 2$ ...............Answer

6 0

3 years ago

Read 2 more answers

A small military base housing 1,000 troops, each of whom is susceptible to a certain virus infection. Assuming that during the c

slava [35]

Answer:

$I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

Step-by-step explanation:

The rate of infection is jointly proportional to the number of infected troopers and the number of non-infected ones. It can be expressed as follows:

$\frac{dI}{dt}=a*I*(1000-I)$

Rearranging and integrating

$\frac{dI}{dt}=a*I*(1000-I)\\\\\frac{dI}{I*(1000-I)}=a*dt\\\\\int\frac{dI}{I*(1000-I)}=\int a*dt\\\\-\frac{ln(1000/I-1)}{1000}+C=a*t$

At the initial breakout (t=0) there was one trooper infected (I=1)

$-\frac{ln(1000/1-1)}{1000}+C=0\\\\-0,006906755+C=0\\\\C=0,006906755$

In two days (t=2) there were 5 troopers infected

$-\frac{ln(1000/5-1)}{1000}+0,006906755=a*2\\\\-0,005293305+0,006906755=2*a\\a = 0,00161345 / 2 = 0,000806725$

Rearranging, we can model the number of infected troops (I) as

$-\frac{ln(1000/I-1)}{1000}+0,006906755=0,000806725*t\\\\-\frac{ln(1000/I-1)}{1000}=0,000806725*t-0,006906755\\-ln(1000/I-1)=0,806725*t-0.6906755\\\\\frac{1000}{I}-1=exp^{0,806725*t-0.6906755} \\\\\frac{1000}{I}=exp^{0,806725*t-0.6906755}+1\\\\I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

6 0

2 years ago

The top tree broke and fell over.the remaining tree teunk is 3 feet tall.the tip of the tree rests on the ground 14 feet from th

Bas_tet [7]

Answer:

14.3 feet.

14.3 feet

Step-by-step explanation:

The problem forms a right triangle in which:

The Vertical Leg of the Right Triangle = 3 feet

The Horizontal Leg of the Right Triangle =14 feet

We are to determine the length of the broken part of the tree. This is the Hypotenuse of the Right Triangle,

Using Pythagoras Theorem

$Hypotenuse^2=Opposite^2+Adjacent^2\\Hypotenuse^2=14^2+3^2\\Hypotenuse^2=205\\Hypotenuse=\sqrt{205}\\Hypotenuse=14.32\\ \approx 14.3 feet $(to the nearest tenth of a foot).\\Therefore, the lenght of the broken part of the tree to the nearest tenth of a foot is 14.3 feet.$

5 0

3 years ago

Please PLEASE HELP ASAP EVERYONE KEEPS PUTTING ABSURD STUFF PLEASEE

levacccp [35]

domain 100 is the answer

3 0

2 years ago