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Andreyy89
3 years ago
8

What is the interquartile range of the numbers 9, 28, 16, 2, 33, 6, 10

Mathematics
1 answer:
Mumz [18]3 years ago
6 0

Answer:

IQR = 22

Step-by-step explanation:

IQR Formula:

IQR = Q3 - Q1

In order you find Q3 and Q1, please follow these steps:

1. First, you need to order the list of numbers from least to greatest:

2, 6, 9, 10, 16, 28, 33

2. Then, you need to find the median, or the middle number.

2, 6, 9, 10, 16, 28, 33

3. In order to find IQR, you must find the first and third quartiles.

2, 6, 9, 10, 16, 28, 33

Q1 = 6

Q3 = 28

This is because 6 basically means that all the numbers leading to 6 would account for 25% of the data while all the numbers leading to 28 would account for 75% of the data, hence why these are called quartiles.

Now since you have Q1 and Q3, you follow the formula.

28 - 6 = 22

IQR = 22

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So to start subtract $5 from $16.25 for the monthly membership
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So then you Just divide...
$11.25 divided by $1.25
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So bill rented 9 movies for the month

Hope this helped! :)
6 0
3 years ago
At the zoo the polar bears are fed from 4 kg bucket of a fish day.If each bears eats 3 upon 5 from that bucket what amount of fi
ser-zykov [4K]

Answer:

2400 grams

Step-by-step explanation:

The bears are fed from a 4 kg bucket each day. If the bears eat 3/5 of that bucket, therefore, the amount of fish that the bears eat is:

3 / 5 * 4 = 2.4 kg

Converting this to grams:

1 kg = 1000 g

2.4 kg = 2.4 * 1000 = 2400 grams

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6 0
4 years ago
A random sample of 84 students at a university showed an average age of 22 years and a sample standard deviation of 3 years. Fin
Debora [2.8K]

Answer:

The margin of error for the 94% confidence interval is 0.6154.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean is:

CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

The margin of error of this interval is:

MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

The critical value of <em>z</em> for 94% confidence level is, <em>z</em> = 1.88.

Compute the margin of error for the 94% confidence interval as follows:

MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

          =1.88\times\frac{3}{\sqrt{84}}\\\\=0.6154

Thus, the margin of error for the 94% confidence interval is 0.6154.

7 0
3 years ago
What is 237 rounded to the nearest ten
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Answer:

240

Step-by-step explanation:

6 0
3 years ago
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Answer:

625 metres

Step-by-step explanation:

Given the area function expressed as a(w)=-(w-25)^2+625.

The maximum area occurs at when da/dw = 0

da/dw = -2(w-25)

0 = -2(w-25)

-2(w-25) = 0

w - 25  = 0

w = 25

Substitute w = 25 into the modeled equation;

Recall a(w)=-(w-25)^2+625.

a(25)=-(25-25)^2+625

a(25) = 0+625

a(25) = 625

Hence the maximum area possible is 625 metres

4 0
3 years ago
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