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liraira [26]
2 years ago
6

How do i slove 7/20.3 division problem step by step

Mathematics
1 answer:
charle [14.2K]2 years ago
6 0
Move the decimal point one to the right on both sides so it would be 70/203. After that you can divide it by adding more 0s to 70. Like, 70.00 until you get an answer
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\bf \begin{array}{ccll} \stackrel{paint}{gallons}&fence\\ \cline{1-2} \\\frac{1}{4}&\frac{2}{3}\\\\ x&1 \end{array}\implies \cfrac{~~\frac{1}{4}~~}{x}=\cfrac{~~\frac{2}{3}~~}{1}\implies \cfrac{~~\frac{1}{4}~~}{\frac{x}{1}}=\cfrac{2}{3}\implies \cfrac{1}{4}\cdot \cfrac{1}{x}=\cfrac{2}{3} \\\\\\ \cfrac{1}{4x}=\cfrac{2}{3}\implies 3=8x\implies \cfrac{3}{8}=x

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3 years ago
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When dividing by a negative the sign changes to the opposite.
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3 years ago
What does (-x)+(-x)+(-x)=
Mazyrski [523]

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-3x

Step-by-step explanation:

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This Dot Plot shows how many books a selection of students read during
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Answer: A

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3 years ago
In a certain community, 30% of the families own a dog, and 20% of the families that own a dog also own a cat. It is also known t
Komok [63]

Answer:

What is the probability that a randomly selected family owns a cat? 34%

What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat? 82.4%

Step-by-step explanation: We can use a Venn (attached) diagram to describe this situation:

Imagine a community of 100 families (we can assum a number, because in the end, it does not matter)

So, 30% of the families own a dog = .30*100 = 30

20% of the families that own a dog also own a cat = 0.2*30 = 6

34% of all the families own a cat = 0.34*100 = 34

Dogs and cats: 6

Only dogs: 30 - 6 = 24

Only cats: 34 - 6 = 28

Not cat and dogs: 24+6+28 = 58; 100 - 58 = 42

What is the probability that a randomly selected family owns a cat?

34/100 = 34%

What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?

A = doesn't own a dog

B = owns a cat

P(A|B) = P(A∩B)/P(B) = 28/34 = 82.4%

5 0
2 years ago
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