If F(x) =g(x) =2x,
x can be any value
Answer:
π/8 radians
Step-by-step explanation:
THIS IS THE COMPLETE QUESTION
In 1 h the minute hand on a clock moves through a complete circle, and the hour hand moves through 1 12 of a circle. Through how many radians do the minute hand and the hour hand move between 1:00 p.m. and 1:45 p.m. (on the same day)?
SOLUTION
✓If the minute hand on a clock moves through complete circle in 1 hour, then it means that it goes through a circle and angle of circle in radians is 2π.
Between 1:00 p.m. and 1:45pm in the same day we have 45 minutes i.e (1.45 pm -1pm)
Within the 1hour minutes, the hand can move with complete cycle of 2π radians
Then At time t= 45minutes
Angle through the circle at 45 minutes= 45/60 ×2π radians
= 3π/2 radians
And if the hour hand goes through a complete cycle 1/12 as told in the question we have 1/2 × 2π radians
For t=45 minutes
Then 1/12 × 2π ×45/60
= π/8 radians
Hence, the minute hand and the hour hand move π/8 radians between 1:00 p.m. and 1:45 p.m.
no it is more than 4x it is 6x
Find rates of change until you find a constant.
dy/dx=1,2,3,4,5,6
d2y/dx2=1,1,1,1,1
So the acceleration, d2y/d2x, is constant. This means that this is a quadratic sequence of the form a(n)=an^2+bn+c. So we can set up a system of equations to solve for the values of a,b, and c. Using the first three points, (1,1), (2,2), and (3,4) we have:
9a+3b+c=4, 4a+2b+c=2, and a+b+c=1 getting the differences...
5a+b=2 and 3a+b=1 and getting this difference...
2a=1, so a=1/2 making 5a+b=2 become:
2.5+b=2, so b=-1/2, making a+b+c=1 become:
1/2-1/2+c=1, so c=1 so the rule is:
a(n)=0.5x^2-0.5x+1 or if you prefer to not have decimals
a(n)=(x^2-x+2)/2
