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Levart [38]
3 years ago
15

15/21 in its simplest form?

Mathematics
2 answers:
garri49 [273]3 years ago
7 0

Answer:

5/7

Step-by-step explanation:

Lunna [17]3 years ago
4 0

Answer:

5/7 i think

Step-by-step explanation:

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In the formula a^2 + b^2 = c^2 , what is the value of a^2 ?
maksim [4K]
The answer would be A. c^2 – b^2 
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6 0
4 years ago
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A polar bear swims 390 meters at a constant rate in 150 seconds. what is the speed of the polar bear?
worty [1.4K]
The answer is 2.6 m/s

The speed (v) is distance (d) through time (t).
v = d/t

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d = 390 m
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v = = 2.6 m/s
5 0
4 years ago
You buy a house for $130000. it appreciates 6% per year. how much is it worth in 10 years
Colt1911 [192]
Growth because “appreciate” 6% per year

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7 0
3 years ago
20(20-x)=300 what is x
neonofarm [45]

Answer:

x = 5

Step-by-step explanation:

20(20-x)=300

1. Divide both sides by 20.

20(20-x)/20 = 300/20

2. Simplify.

20-x=15

3. Subtract 20 from both sides.

20-x-29=15-20

4. Simplify.

-x=-5

5. Divide both sides by -1.

-x/-1 = -5/-1

6. Simplify.

x=5

5 0
3 years ago
The disk enclosed by the circle x+y = 4 is revoived about the y-axis to generate solid sphere. A hele of diameter 2 units is the
Vesnalui [34]

Step-by-step explanation:

Suppose we have a curve, y = f(x).

y = f(x)

x = a x = b

Imagine that the part of the curve between the ordinates x = a and x = b is rotated about the

x-axis through 360◦

. The curve would then map out the surface of a solid as it rotated. Such

solids are called solids of revolution. Thus if the curve was a circle, we would obtain the surface

of a sphere. If the curve was a straight line through the origin, we would obtain the surface of

a cone. Now we already know what the formulae for the volumes of a sphere and a cone are,

but where did they come from? How can they calculated? If we could find a general method

for calculating the volumes of the solids of revolution then we would be able to calculate, for

example, the volume of a sphere and the volume of a cone, as well as the volumes of more

complex solids.

To see how to carry out these calculations we look first at the curve, together with the solid it

maps out when rotated through 360◦

.

y = f(x)

Now if we take a cross-section of the solid, parallel to the y-axis, this cross-section will be a

circle. But rather than take a cross-section, let us take a thin disc of thickness δx, with the face

of the disc nearest the y-axis at a distance x from the origin.

www.mathcentre.ac.uk 2

6 0
3 years ago
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