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Vaselesa [24]
3 years ago
12

Nima uses 2/3 cup peanuts, 1/2 cup cashews , 3/4 cup pecans, and some raisins in a recipe that makes 2 1/4 cups of trail mix. Ho

w many cups of peanuts are there per cup of trail mix? in simplest form.hurry pls
Mathematics
1 answer:
aliina [53]3 years ago
8 0

Answer: There are 2/3 cups of peanuts and 21/4 cups of trail mix if you are to subtract the two witch gives you 4.58333333333 then simplify that as a fraction  u should get 41/2 then simplify that u should get  20 or 1/2

Step-by-step explanation:

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1/5 (18-11) I believe this is what you mean?
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Volume ....................
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360 cm^2

Step-by-step explanation:

length x width x height

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North America burned 4.5 x 1016 btu of petroleum in 1998. At this rate, how many BTU's will be burned in 9 year?
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Suppose a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%. A cell phon
leva [86]

Answer:

We conclude that the actual percentage of households is equal to 30%.

Step-by-step explanation:

We are given that a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%.

Their marketing people survey 150 households with the result that 43 of the households have three cell phones.

Let p = <u><em>proportion of households that have three cell phones NOT known.</em></u>

So, Null Hypothesis, H_0 : p = 30%      {means that the actual percentage of households is equal to 30%}

Alternate Hypothesis, H_A : p \neq 30%     {means that the actual percentage of households different from 30%}

The test statistics that would be used here <u>One-sample z-test for proportions;</u>

                                T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of households having three cell phones = \frac{43}{150} = 0.29

           n = sample of households = 150

So, <u><em>the test statistics</em></u>  =  \frac{0.29-0.30}{\sqrt{\frac{0.30(1-0.30)}{150} } }  

                                     =  -0.27

The value of z test statistic is -0.27.

<u>Also, P-value of the test statistics is given by;</u>

              P-value = P(Z < -0.27) = 1 - P(Z \leq 0.27)

                            = 1 - 0.6064 = <u>0.3936</u>

<u>Now, at 1% significance level the z table gives critical value of -2.58 and 2.58 for two-tailed test.</u>

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <em><u>we fail to reject our null hypothesis</u></em>.

Therefore, we conclude that the actual percentage of households is equal to 30%.

4 0
3 years ago
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