Here it is given that AB || CD
< EIA = <GJB
Now
∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)
∠EIA ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)
∠IKL + ∠IKC 180° and ∠DLH + ∠JLD =180° (Linear Pair Theorem)
So
m∠IKL + m∠IKC = 180° ....(1)
But ∠IKC ≅ ∠JLD
m∠IKC = m∠JLD (SUBTRACTION PROPERTY OF CONGRUENCY)
So we have
m∠IKL + m∠JLD = 180°
∠IKL and ∠JLD are supplementary angles.
But ∠DLH and ∠JLD are supplementary angles.
∠IKL ≅ ∠DLH (CONGRUENT SUPPLEMENTS THEOREM)
Every linear graph is just a straight line, so if there are any curves or unnatural shapes, than you know it is not linear. As for equations, if it can be shaped into y=mx+b where m and b are numbers, then it will be a linear equation.
Answer:
Q1:
Share of the daughter (x):
2x + x + x + $1,000 = $9,000
4x = $8,000
x = $2,000
Share of the wife:
= 2($2,000)
= $4,000
Share of the son:
= $2,000 + $1,000
= $3,000
Answer: wife, $4,000; son, $3,000; daughter, $2,000
Q2:
= 1/2x + $1,000
Answer: 1/2x + $1,000: expression for share of the son
Proof (the wife shares $4,000):
Share of wife (x):
x + 1/2x + 1/2x + $1,000 = $9,000
2x = $8,000
x = $4,000
Step-by-step explanation:
hope it helps!
Answer:
Missing constant: 100
Step-by-step explanation:
perfect square (a - b)^2 = a^2 - 2ab + b^2
In this case
20x = 2 * x * 10
and
10^2 = 100
so
(x - 10)^2 = x^2 - 20x + 100
