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Andre45 [30]
Answer:
the one real zero is in the interval (-1, 0)
Step-by-step explanation:
Descartes' rule of signs tells you there are 0 or 2 positive real zeros. Changing the signs of the odd-degree terms and applying that rule again tells you there is one negative real zero. At the same time, those coefficients (-3, -5, -5, +7) have a negative sum, so you know ...
f(-1) = -6
f(0) = +7
so there is a zero in the interval (-1, 0).
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You can try a few values between x=0 and x=10 to see what the function does in that part of the graph. You find ...
f(1) = 10
f(2) = 21
f(3) = 58
So, it is safe to conclude that there are no real zeros for x > 0.
The only real zero of f(x) is in the interval (-1, 0).
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I like to use a graphing calculator for problems like this.
Answer:
the answer would be -4x
Step-by-step explanation:
dividing (-20xyz) by (5zy) = 3
Three and twenty-nine ten-thousandths
Problem 10
You are correct. The answer is choice C. The cm^3 notation represents cubic centimeters, which is a unit for volume. Think of a 1 cm by 1 cm by 1 cm cube.
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Problem 11
This problem is a bit strange. She borrows money ($100) but then it says she earns $300 per day. It makes no mention of her paying that $100 back, or when it's due back. I'll just assume that she keeps the $100 for the 12 days.
If that assumption is correct, then she'll have y = 300x+100 dollars after x days.
Plug in x = 0 and you'll get y = 100. Plug in x = 12 and you'll end up with y = 3700. Therefore, the two points on this graph are (0,100) and (12,3700).
The only window that has y = 3700 in it is the interval 
while the other windows are too small. So only choice D is the answer here. In other words, you'll have "yes" on choice D, and "no" on everything else.
In fraction 100/100
In mixed number 10 0/10
Simplest form = 100
I hop this helps! :)
