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ivann1987 [24]
3 years ago
15

Write an algebraic expression for the following: An electrician charges a $50 house call fee and $65 per hour for the work. *

Mathematics
2 answers:
frozen [14]3 years ago
8 0
The answer is y=65x+50
kobusy [5.1K]3 years ago
7 0
C. 65t + 50. Hope that helps :)
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HELP PLEASE!
Svet_ta [14]
Hello! I believe the answer to your question is C (hours). If t is the amount of time it takes, hours is a unit of time, therefore I assume that would be your answer. :)
7 0
4 years ago
nstead of having 1.5 times as many pink flowers as white flowers, Molly has decided to plant a garden with twice as many pink fl
Kitty [74]

Answer:

2, 3, and, 4

Step-by-step explanation:

Pink=P

White=W

The equation in this question is modeled by:

P=2W

So all you need to do is put the numbers in this equation!

4=2W\\6=2W\\8=2W

The answers would be:

2, 3, and, 4

3 0
4 years ago
Read 2 more answers
Find the perimeter and area of this figure
Sonja [21]

Answer:

A = (16π -32) in²

P = (4π +8√2) in

Step-by-step explanation:

The area is that of a quarter-circle of radius 8 inches less half the area of a square with side length 8 inches. Two formulas are useful:

area of a circle = πr² . . . . .r = radius

area of a square = s² . . . . s = side length

Then your area is ...

A = (1/4)π(8 in)² - (1/2)(8 in)² = (64 in²)(π/4 -1/2)

A = (16π -32) in²

____

The applicable formulas for the side lengths of your figure are ...

arc BD = (1/4)(2πr) = π(r/2) = π(8 in)/2 = 4π in

segment BD = (8 in)√2

The perimeter is the sum of these lengths, so is ...

P = (4π +8√2) in

_____

Of course, you are very familiar with the fact that an isosceles right triangle with side lengths 1 has a hypotenuse of length √(1²+1²) = √2. Scaling the triangle by a factor of 8 inches means the segment AB will be 8√2 inches long.

8 0
3 years ago
An eight character password uses four digits 1-6 and four letters A-Z with repeats allowed. How many possible passwords like thi
Ratling [72]
4 x 8 x 6 x 4 x 26 = 19,968

i think however, i could be wrong. my teacher told me to use the fundamental counting principle. you multiply each different part of the problem.
3 0
4 years ago
Why are halves a good choice for benchmark fractions for 1 1/3
VARVARA [1.3K]

Answer:

Following are the answer to this question:

Step-by-step explanation:

For calculating, matching, or arranging certain fractions, the benchmark fraction can be described as common fractions, that can be calculated or judged. It is most useful when measuring fractions to comparisons in a number line.

Given value:

\to 1 \frac{1}{3} = 1+\frac{1}{3} \\

         = 1+ \frac{1}{6}+\frac{1}{6}\\

3 0
3 years ago
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