All categories

3 years ago

Please i need an answer right now

Mathematics

1 answer:

AVprozaik [17]3 years ago

5 0

Answer:

let the number of meals = m

Then price ,P = 75m
dependent variable = P
independent variables = m
P = 75*12 =900
m = 2000÷ 75 = max 26 meals

mark me as brainliest ❤️

You might be interested in

At a school with 100? students, 33 were taking? Arabic, 32 ?Bulgarian, and 40 Chinese. 9 students take only? Arabic, 12 take onl

Stels [109]

Answer: The answer is 4 and 32.

Step-by-step explanation: Let "A", "B" and "C" represents the set of students who were taking Arabic, Bulgarian and Chinese respectively.

The, according to the given information, we have

$n(A)=33,~~n(B)=32,~~n(C)=40,~~n(A\cap B)=14.$

Let 'p' represents the number of students who take all the three languages, then

$n(A\cap B\cap C)=p.$

Also,

$n(A)-n(A\cap B)-n(A\cap C)+n(A\cap B\cap C)=9\\\\\Rightarrow n(A\cap B)+n(A\cap C)=24+p~~~~~~~~~~~~~~(a),\\\\n(A\cap B)+n(B\cap C)=20+p~~~~~~~~~~~~~~(b),\\\\n(B\cap C)+n(A\cap C)=20+p~~~~~~~~~~~~~~~(c).$

From here, we get after subtracting equation(c) from (b) that

$n(A\cap B)=n(A\cap C)=14.$

Therefore,

$p=14+14-24=4,$ and from equation (a), we find

$n(B\cap C)=24-14=10.$

Thus,

$n(A\cap B\cap C)=4$ and

$n(A\cup B\cup C)=n(A)+n(B)+n(C)-n(A\cap B)-n(B\cap C)-n(A\cap C)+n(A\cap B\cap C)\\\\\Rightarrow n(A\cap B\cap C)=33+32+40-9-12-20+4\\\\\Rightarrow n(A\cap B\cap C)=68.$

Thus, the number of students who take all the three languages is 4 and the number of students who take none of the languages is 100-68 = 32.

5 0

3 years ago

How many times will 1/4 go into 6 7/10?

Firlakuza [10]

Answer: 93 and 4/5

Step-by-step explanation:

6 7/10 divided by 1/14

= 67/10 divided by 1/14

= 67/10 x 14/1

= 67/5 x 7/1

= 469/5

3 0

3 years ago

What is the value of y=2(1.5)^x +3 when x=2

Inessa05 [86]

Answer:

y=7.5

Step-by-step explanation:

2*1.5ˣ+3=

substitute 2 for x

2*1.5²+3=

2*2.25+3=

4.5+3

y=7.5

5 0

3 years ago

Plot 7 > c on a number line

harina [27]

0----------5------7======================>
hope this helps

7 0

3 years ago

If (x)=3x-1 and s(x)=2x+1, which expression is equivalent to r over s (6) ?

katrin [286]

Answer:

$\large\boxed{\dfrac{3(6)-1}{2(6)+1}}$

Step-by-step explanation:

$\left(\dfrac{f}{g}\right)(x)=\dfrac{f(x)}{g(x)}\\\\\text{We have}\\\\f(x)=3x-1,\ g(x)=2x+1\\\\\left(\dfrac{f}{g}\right)(x)=\dfrac{3x-1}{2x+1}\\\\\left(\dfrac{f}{g}\right)(6)\to\text{put x = 6 to the equation of the function}\ \left(\dfrac{f}{g}\right)(x):\\\\\left(\dfrac{f}{g}\right)(6)=\dfrac{3(6)-1}{2(6)+1}$

6 0

3 years ago