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Illusion [34]
3 years ago
6

Help please ASAP please I’ll mark you as brainlister

Mathematics
1 answer:
storchak [24]3 years ago
4 0

Answer:

a = 4

Step-by-step explanation:

\sin(theta)  =  \frac{opposite}{hypotenuse}

\cos(theta)  =  \frac{adjacent}{hypotenuse}

\tan(theta)  =  \frac{opposite}{adjacent}

hypotenuse = a

opposite = 2√3

adjacent = b

theta = 60°

the best formula to use is the first formula cause we have all the values to substitute in it in order to find the value of a

\sin(60)  =  \frac{2 \sqrt{3} }{a}

\frac{2 \sqrt{3} }{ \sin(60) }  = a

4 = a

a = 4

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B) 54°C as 130°F is 54,44°C
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What is 9+10 <br>what is 9+10​
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Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
6C + 47M=893.50<br> 25C + 22M=527.86
Olenka [21]

Answer:

C = 4.94   M = 18.38

Step-by-step explanation:

the easiest way is to graph both equaitons and see where they intersect,

see the image

or solve by substitution

6C + 47M=893.50           C = (893.50 - 47M)/6

25C + 22M=527.86

25((893.50 - 47M)/6)  + 22M = 527.86

25/6 [(893.50) - 47M] + 22M = 527.86

25/6 [ - 47M] + 22M = 527.86 - 25/6 [(893.50)

22M - 25(47M)/6  = -3195.06

22M - 195.83M  = -3195.06

      -173.83M   =   -3195.06

                 M  =  18.38

C = (893.50 - 47(18.38)/6

C = 4.94

6 0
3 years ago
Write the polar equation in rectangular form.
zhuklara [117]

Answer:

Step-by-step explanation:

The identities you need here are:

r=\sqrt{x^2+y^2}  and   r^2=x^2+y^2

You also need to know that

x = rcosθ  and

y = rsinθ

to get this done.

We have

r = 6 sin θ

Let's first multiply both sides by r (you'll always begin these this way; you'll see why in a second):

r² = 6r sin θ

Now let's replace r² with what it's equal to:

x² + y² = 6r sin θ

Now let's replace r sin θ with what it's equal to:

x² + y² = 6y

That looks like the beginnings of a circle.  Let's get everything on one side because I have a feeling we will be completing the square on this:

x^2+y^2-6y=0

Complete the square on the y-terms by taking half its linear term, squaring it and adding it to both sides.

The y linear term is 6.  Half of 6 is 3, and 3 squared is 9, so we add 9 in on both sides:

x^2+(y^2-6y+9)=9

In the process of completing the square, we created within that set of parenthesis a perfect square binomial:

x^2+(y-3)^2=9

And there's your circle!  Third choice down is the one you want.

Fun, huh?

5 0
3 years ago
A quantity a varies inversely as a quantity b, if, when b changes a changes in the inverse ratio. What happens to the quantity a
Julli [10]

Answer:

quantity a is halfed

Corrected question;

A quantity a varies inversely as a quantity b, if, when b changes a changes in the inverse ratio. What happens to the quantity a if the quantity b doubles?

Step-by-step explanation:

Analysing the question;

A quantity a varies inversely as a quantity b,

a ∝ 1/b

a = k/b ......1

when b changes a changes in the inverse ratio;

Since the change at the same ratio but inversely, k = 1

So, equation 1 becomes;

a = 1/b

If the quantity b doubles,

ab = 1

a1b1 = a2b2

When b doubles, b2 = 2b1

a1b1 = a2(2b1)

Making a2 the subject of formula;

a2 = a1b1/(2b1)

a2 = a1/2

Therefore, when b doubles, a will be divided by 2, that means a is halfed.

3 0
3 years ago
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