<span>The quadrilateral ABCD have vertices at points A(-6,4), B(-6,6), C(-2,6) and D(-4,4).
</span>
<span>Translating 10 units down you get points A''(-6,-6), B''(-6,-4), C''(-2,-4) and D''(-4,-6).
</span>
Translaitng <span>8 units to the right you get points A'(2,-6), B'(2,-4), C'(6,-4) and D'(4,-6) that are exactly vertices of quadrilateral A'B'C'D'.
</span><span>
</span><span>Answer: correct choice is B.
</span>
The solution to the inequality 6m + 2 > -27 is m > -4.33
The solution to the inequality 8(p-6)>4(p-4) is p > 8
The given inequality is:
6m + 2 > - 27
Subtract 2 to both sides of the inequality
6m + 2 - 2 > -27 - 2
6m > -29
Divide both sides by 6

For the inequality 8(p-6)>4(p-4)
Expand the inequality using the distributive rule
8p - 48 > 4p - 16
Collect like terms
8p - 4p > -16 + 48
4p > 32
Divide both sides of the inequality 4

The solution to the inequality 6m + 2 > -27 is m > -4.33
The solution to the inequality 8(p-6)>4(p-4) is p > 8
Learn more here: brainly.com/question/15816805